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Apr
10
comment Fix my code to return a table of values
how did you figure how to call it with no example given? very good. But I see no DO LOOP in your answer like the teacher code? ;)
Apr
10
reviewed Approve Fix my code to return a table of values
Apr
10
comment Fix my code to return a table of values
A call example to the function defined is needed
Apr
9
revised many indefinite integrals do not evaluate in 10.1, looking for the cause
added bugs tag
Apr
9
answered Solving differential equation
Apr
9
awarded  Nice Question
Apr
9
comment Plot roots of polynomial system of equations in 3 variables
@user27616 I am not following you exactly, but there are lots of Contour related functions in Mathematica, and also options to control what they show and how. If you have problem or question with specific implementation or how to use it, it would be better to post that as separate question.
Apr
9
comment Plot roots of polynomial system of equations in 3 variables
@user27616 here is screen shot from my notebook !Mathematica graphics make sure you type your equations as shown in the screen shot and above, not like you had them
Apr
9
revised Plot roots of polynomial system of equations in 3 variables
copy typo
Apr
9
revised Plot roots of polynomial system of equations in 3 variables
added solution
Apr
9
answered Plot roots of polynomial system of equations in 3 variables
Apr
9
revised many indefinite integrals do not evaluate in 10.1, looking for the cause
added screen shot
Apr
9
revised many indefinite integrals do not evaluate in 10.1, looking for the cause
added more screen shot
Apr
9
revised many indefinite integrals do not evaluate in 10.1, looking for the cause
add second screen shot
Apr
9
revised many indefinite integrals do not evaluate in 10.1, looking for the cause
added screen shot
Apr
9
asked many indefinite integrals do not evaluate in 10.1, looking for the cause
Apr
9
answered How do I map a function onto the result of an expression that already has a pure function as an argument
Apr
9
comment How to get the modulus of following complex number
@Ben, the help reference.wolfram.com/language/ref/ComplexExpand.html really explains it well. Basically, if you type Abs[x + I y], then M can't do Sqrt[(x^2+y^2)] since x and y themselves can be complex numbers, each with real and imaginary parts. If that was the case, then x^2 will contains a complex value in it. So someone came up with a function to tell M to assume all symbols are real.
Apr
9
answered How to get the modulus of following complex number
Apr
8
awarded  bugs