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4h
comment I need to solve the Mathieu equation: $y''(x)+(a−2q \cos(2x))y(x)=0$
did you try DSolve? I do not understand what you mean by integer order and $\pi$ periodicity?
7h
comment Manipulate on Mathematica Online
I have not tried Manipulate in the cloud for sometime, since when I tried it initially, many Dynamics did not work. Here is a link that lists something that did not work then Cloud Dynamic support
1d
comment DE: Plotting a functional
it is hard to read your code.
1d
comment How can I avoid to define public all methods in a package
you only make usage:: for functions that are to be called from outside. Not for all the variables. It is similar to Java class or C++ class, where you make public functions.
2d
answered Plotting direction fields along with trajectories
2d
comment Integral equation
This is not really an integral equation. The upper limit of the integral has to be z in your example, which is the independent variable in f(z) for it to be called integral equation? How did you handle the derivative of the absolute term there?
May
26
comment Listing elements starting from 0
@Prahar There is nothing wrong with using these options for small code. But I was thinking when the code gets larger, and you have many functions, it can get confusing if some code uses index 1 and another uses index 0. Also the Notation package option requires loading it each time. So this makes it harder to share code with others. But you try them and decide if these work for you. See this note on the subject.
May
26
answered Listing elements starting from 0
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
@Guesswhoitis. I agree. This is a math question really, not Mathematica.
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
@Guesswhoitis. yes, but that is what I mean, now solve for $x$ from the above, and take series expansion of the RHS, then equate the $x$ coeffcients. There will be one term in the series with $x$ in it. That is what I meant.
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
How taking the logs of both sides, then separate $x$ by itself in terms of all the others terms (which will have $x$ in them), you get $x=\frac{\ln(y)-ln(1-x)}{ln(x)-ln(1-x)}$ and then take series expansion of the RHS in $x$, and then equate the $x$ coefficients, so you get $1=\frac{log(x)-log(y)}{log(x)^2}$ and now solve this for $x$ which gives E^(1/2 (1 - Sqrt[1 - 4 Log[y]])) with complicated conditionals. warning, I am not a math major, since the above might not make sense math wise, but something to look at.
May
22
awarded  equation-solving
May
21
comment NDSolve and assuming
on use of assumptions: DSolve and NDSolve do not use assumptions themselves. I can't find the reference on this now, but this came up before. Here is dsolve-will-not-apply-assumption question on assumptions with DSolve
May
21
revised Does the equation have two roots?
update finding on maple fsolve
May
21
answered Does the equation have two roots?
May
20
comment Roots of Whittaker W function
@Guesswhoitis. I did try it before commenting. They are tiny and they all went away after Chop. V 10.1
May
20
comment Roots of Whittaker W function
One issue is that they all have a nonzero imaginary component To clean, use Chop it is floating point computation noise.
May
20
comment How can I mark a point on a slider control?
@glance the tick is the control variable used to control everything. a control variable has to appear in the Manipulate expression somewhere to be tracked.
May
20
comment Are there any open source projects related to signal processing
You can't buy the DSP app anymore. I have it since I bought it long time ago, but it does not run anymore on new versions of M. Check this site which I think is the origin of that application from long time ago by Brian Evans.
May
20
comment Are there any open source projects related to signal processing
There used to be Mathematica DSP application, but most of that functionality are integrated to Mathematica now (not open source ofcourse ;)