| bio | website | |
|---|---|---|
| location | Europe | |
| age | ||
| visits | member for | 1 year, 2 months |
| seen | 10 mins ago | |
| stats | profile views | 202 |
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May 6 |
revised |
Sync Animated Plots added 46 characters in body |
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May 6 |
awarded | Nice Answer |
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Apr 17 |
revised |
Colorbar doesn't appear added 6 characters in body; edited tags; edited title |
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Apr 15 |
awarded | Popular Question |
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Apr 12 |
awarded | Nice Answer |
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Mar 30 |
answered | HighlightGraph with style |
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Mar 29 |
revised |
FindClusters for 3D Pancake/Platelet Shapes added 54 characters in body |
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Mar 20 |
comment |
X-Y scatter plot with coloring dependent on Z value Similar question: mathematica.stackexchange.com/q/21130/685 |
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Mar 19 |
comment |
How can I define a Step-Wise function in Mathematica (Not using Heaviside Step Function)? Indeed, that's how you can use it. |
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Mar 19 |
comment |
How can I define a Step-Wise function in Mathematica (Not using Heaviside Step Function)? Take a look at Piecewise. |
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Mar 19 |
comment |
Exporting large numbers to a text file You can use NumberForm with the option ExponentFunction: NumberForm[123456.789, {20, 3}, ExponentFunction -> (Null &)] |
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Mar 18 |
comment |
How can I invert the colors in a color bar Try replacing colorbar[valrange, cf] with colorbar[valrange, ColorData[cf][1 - #] &] at the end of your example. |
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Mar 16 |
comment |
Pretty way to group elements at odd and even positions @Mr.Wizard Ha, I've just seen now that in the docs for Span it says m[[i;;j;;k]] is equivalent to Take[m,{i,j,k}]. Well, let's say that mine is more readable for novice users. |
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Mar 16 |
answered | Pretty way to group elements at odd and even positions |
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Mar 12 |
awarded | Nice Answer |
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Mar 12 |
revised |
How can I compile a ColorFunction with Blend? deleted 1 characters in body |
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Mar 12 |
comment |
Coloring Points in a Plot, based on their position in the list Maybe it is worth pregenerating all the solutions of your ODE and use those in your Manipulate function. Take a look also at Mr.Wizard's solution to speed up rendering of ListPolarPlot. |
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Mar 12 |
comment |
Coloring Points in a Plot, based on their position in the list @Mr.Wizard I fully agree with your comment and I support solutions based on Graphics primitives. Since the question was based on a ListPolarPlot I gave a solution that holds for this function. |
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Mar 12 |
comment |
Coloring Points in a Plot, based on their position in the list BTW, instead of typing Transpose[position][[1]] you can get the same result with position[[All, 1]]. |
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Mar 12 |
answered | Coloring Points in a Plot, based on their position in the list |