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Aug
21
comment How to find numerically all roots of a function in a given range?
Er... have you guys ever seen this? library.wolfram.com/infocenter/Demos/4482 (Back in the days, Ted Ersek's RootSearch was all the rage on MathGroup) - Yeah, I know, it will come up it has been used below somewhere and I did not pay enough attention...)
Jul
25
awarded  Quorum
Jul
14
reviewed Approve Volumetric Rendering of cylinder symmetric radial image
Jul
14
comment How to draw curvy arrow at the edge of a cylinder
Posters might want to create a CurvyArrow function with the following interface: CurvyArrow[ {startpoint, endpoint}, {offsetstart, offsetend},polarization], with given start and end points, an offset in position as given by the builtin Arrow, and a polarization parameter specifying the plane in which the wiggly line should reside (maybe via the normal vector to said plane?). That should be fairly general and useful to many readers. I would also call that PhotonArrow. Hey, I hope you don't expect me to do all the work!
Jul
14
comment How to draw curvy arrow at the edge of a cylinder
I guess he wanted the little red arrows to be 'photon-like'.
Jul
11
comment Summing complex numbers
What do you mean by "2[Pi]"?
Jul
11
comment LogPlot does not show all points
Just a side note: you can shorten var = range[[1]], xmin = range[[2]], xmax = range[[3]] in {var, xmin, xmax} = range
Jun
22
reviewed Approve Is there any Mathematica functionality enabling its use for the blind?
Jun
17
answered I need F(x,y) = xy (not x*y) e.g. x= 1, y =2 so F(x,y) = 12
Jun
4
comment Finding the discrete Fourier transform for a simple oscillator?
mathematica.stackexchange.com/questions/18082/…
Jun
4
reviewed Approve Import an RDATA, SPSS, SAS, or STATA file into Mathematica
May
30
reviewed Approve How to do color-fill in images in Mathematica?
May
30
reviewed Approve Change the inner color of markers
May
29
awarded  Necromancer
May
24
revised Problem with ReadList, record separator is not working
added formatting
May
24
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
Here, I did it again. I wrote "to" instead of "too" and I corrected the wrong one. And now it's to late to fix it. I hate being me. :-)
May
24
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
@DanielLichtblau :-) Er... that is just an addition to my comment above. When I realized I missed a bit it was to late too edit it... so I had to make a new comment. The ellipses are just 'cut&paste' indicators. Unless you are referring to the above closing ellipses. In that case there's no continuation. All I meant is that once one has seen that "L to gun" gesture, inverse functions are no longer a mistery... (<--- here we go again)
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
...in 0-1 AND it's not monotonic, SO...
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
People here are too fast in killing threads. Relax folks, give a little leeway to new users and see what happens... It's not like virginity in the Middle Ages.
May
23
comment Solution to $y = x^x (1-x)^{(1-x)}$ for $x$
Actually, if you draw the function y[x] you can see that it has real values for x in 0-1, so the inverse function, restricted to reals, has two branches. One is the one you showed, the other one is the mirror of that with respect with the translated y axis at x=1/2. (It's like a "C"). And you can see that by exchanging the x and y axis in the plot of y[x] (there's a simple gesture that changes an "L" made with index and thumb into a "gun" that shows the required transformation to get the inverse of any plot, once one has seen that...)