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  • 10 votes cast
Jun
16
awarded  Critic
Feb
28
comment Permanent minors
That actually made me laugh out quite loud.
Feb
28
accepted Permanent minors
Feb
28
comment Permanent minors
Actually, that answers my question perfectly. I did not know you could give a third argument to Minors, this is absolutely perfect.
Feb
28
awarded  Scholar
Feb
28
awarded  Supporter
Feb
28
comment Permanent minors
Heh, that's clever. Thanks a bunch! =D
Feb
28
awarded  Student
Feb
28
comment Permanent minors
Make a call to Minors[Array[Subscript[a,##]&,{n,n}],k] for any n and k<n, then replace all minus signs by plus signs =)
Feb
28
comment Permanent minors
That gives me the permanent of a matrix, not the permanent minors.
Feb
28
asked Permanent minors
Feb
20
awarded  Autobiographer