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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 3 months |
| seen | Mar 24 at 21:05 | |
| stats | profile views | 43 |
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Feb 16 |
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Method that can be used to collect the variables of a function How about Sequence @@ f[x, y, z]? |
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Jan 22 |
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An apparently “simple” limit? @Kagaratsch: 1 is the correct result.... |
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Dec 15 |
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Remove annoying Conjugate It is actually interesting that Mathematica does not realise that the Sqrt are harmless. In fact, it can simplify the expression when removing the -2 and having the assumptions Im[es]==Im[kx]==Im[ky]==0. |
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Sep 11 |
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How to tell Mathematica that a function is dependent on other variables? Nice: +1 (and some more characters) |
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Aug 12 |
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Change variables in differential expressions I do not think the chain rule is applied correctly. If I use expr[r_]:=D[b[r],r] and then evaluate expr[1/x] I get b'[x] and not -b'[x] x^2... |
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Jul 11 |
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How can I get Mathematica to simplify $\Vert\{1,\sin(t),\cos(t)\}\Vert_2$ to $\sqrt{2}$? @term-rewritica: no, you are right $\cos^2 x + \sin^2 x$ is always 1. However $|\cos x|^2+ | \sin x|^2$ is not always equal to 1. |
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Jun 6 |
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How can I eliminate a function in a system of PDEs, Maple-style? An even easier question would be: how can one eliminate a function in a set of ordinary differential equations using Mathematica. |
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Jun 5 |
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Different determinants on 2 different computers @Öskå: Eigenvalues[{A,B}] solves the problem $\det(A - \lambda B)=0$ for $\lambda$; however in a numerically stable version unlike writing down the polynomial equation for $\lambda$ and then solving it... |
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May 4 |
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Constructing a function with Flat and OneIdentity attribute with the property that otimes[a]:>a Thank you: this is exactly the problem I was suffering. In fact, I did know that Flat affects the pattern matching but I did not know that for a pattern only the attributes at the time when it is set are important and that the attributes are then stored. |
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May 3 |
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Constructing a function with Flat and OneIdentity attribute with the property that otimes[a]:>a Thanks for your question. I figured out that my example was a bit to minimal. I changed the question such that now it is clear where the infinite recursion appears. |
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May 3 |
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Constructing a function with Flat and OneIdentity attribute with the property that otimes[a]:>a Sorry for the confusion. I tried to find a minimal example and it was too minimal (and I did not see that some old Attributes were still set). I edit the question... |
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May 3 |
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Constructing a function with Flat and OneIdentity attribute with the property that otimes[a]:>a @Rojo: otimes[anything] |
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May 3 |
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Constructing a function with Flat and OneIdentity attribute with the property that otimes[a]:>a @MarkMcClure: it also does not work with NonCommutativeMultiply. NonCommutativeMultiply[a] remains unevaluated. |
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Apr 25 |
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Incorrect results for elementary integrals when using Integrate @Searke: thank you for the suggestion, I will do so. |
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Apr 25 |
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Incorrect results for elementary integrals when using Integrate @Szabolcs: the condition which has to be met is $\operatorname{Re} x > 0$. However, I do not believe that it is because of this condition that the integral cannot be performed. Mathematica also does not produce a result for the specific case $x=1$. |
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Apr 25 |
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Incorrect results for elementary integrals when using Integrate Oh, my mistake. |
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Mar 12 |
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Does Mathematica have advanced indexing? @nikie: you are implicitly assuming that the elements of evaluatedCondition are either 0 or 1. This is not always the case (see the code for the || part). I guess the code should be modified slightly not to produce strange result in the case that the condition invokes an Or statement. |
