| bio | website | nl.linkedin.com/in/scdevries |
|---|---|---|
| location | Utrecht, Netherlands | |
| age | ||
| visits | member for | 1 year, 4 months |
| seen | 2 hours ago | |
| stats | profile views | 1,707 |

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2h |
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Import/Export Cluster Object This data type can be saved as any other using the methods described here. Voting to close as duplicate. |
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6h |
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Import/Export Cluster Object You probably want Save or DumpSave. Import/Export using the "WDX", "Package" or "NB" formats may be options too. |
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7h |
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Import/Export Cluster Object What did you do to Import and Export? |
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14h |
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Eureqa Client to connect to Mathematica under Windows You might also be interested in a similar program with very strong ties to Mathematica: evolved-analytics.com/?q=datamodeler/keyfeatures |
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14h |
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Eureqa Client to connect to Mathematica under Windows A Mathematica client here:github.com/shanecelis/eureqa-mathematica-client |
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15h |
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Eureqa Client to connect to Mathematica under Windows I have used Eureqa and it's a nice tool, but I'm not aware of any Mathematica link. It's easy enough to copy the results from the Eureqa program manually. There is an easy API that you might try: code.google.com/p/eureqa-api |
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15h |
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Extracting points data from a 3D curve surface? You could wrap EventHandler around the points similar to my answer here. |
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15h |
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How can I import images from a Microsoft SQLServer database? @subbu en.wikipedia.org/wiki/Hexadecimal |
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15h |
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Extracting points data from a 3D curve surface? Why don't you fit your data with some model and then remove the point with the largest deviations? |
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15h |
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How can I import images from a Microsoft SQLServer database? @subbu 0x is just a convention marking the string as a hexadecimal value. |
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23h |
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Extracting points data from a 3D curve surface? Useful: mathematica.stackexchange.com/questions/16925/… and mathematica.stackexchange.com/questions/3015/… |
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1d |
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How can I import images from a Microsoft SQLServer database? Why do you use FromCharacterCode? Why do you take the [[1,1]] part of the result? Could you provide a longer and more exact example of what binarydata looks like? Are you sure it's a GIF image? |
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2d |
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Distribution above pointplot mathematica.stackexchange.com/questions/4059/… might help too. |
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2d |
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How can I import images from a Microsoft SQLServer database? Did you read the documentation on DatabaseLink? If yes, what did you try and what went wrong? |
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2d |
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Translating a “Point-to-Triangle” distance script from MATLAB to Mathematica I hope this doesn't sound too unfriendly, but this isn't really a code review site; at least, not for long and bulky code. This looks like a rather tedious job and my bet would be a misplaced bracket or another typo error. |
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May 15 |
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Solving for variables in a series of nonlinear equations It is. You'd have a free parameter. |
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May 15 |
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Concerning ShowLegend in Mathematica [cont...] The way plots are generated and combined changed considerably in v6. Specifically, the plot output itself used to be a side effect of the function and it needed to be suppressed by DisplayFunction -> Identity if all one wanted was to store the plot for later combination with other plots. With versions 6 and higher, the plot became the main effect of the plot function and it can be directly combined with other plots in a Show or assigned to variables without generating unwanted extra plots. A ; suppresses graphics output just like it does for numerical output. |
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May 15 |
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Concerning ShowLegend in Mathematica The whole DisplayFunction maneuvering that the code is doing is very pre version 6. [cont...] |
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May 15 |
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Solving for variables in a series of nonlinear equations You could rewrite the equation using two parameters d and e, to get it in the form of f[x_]= d x + e and fit that. d and e can be found using CoefficientList[(660 (-0.37 + b) (x - c))/(660 + a) - 0.37 c, x]. After finding d and e from the fit you can solve for a, b and c. |
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May 15 |
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Reducing exponential inequalities fails In version 9 I only get a message with the third Reduce. The first Reduce also gets a better solution of (N > 1 && x < y) || (0 < N < 1 && x > y). |