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Jun
27
reviewed Reopen Solving for any one variable in a formula given values for all the others
Jun
26
comment Convert spreadsheet (Excel) to *.csv during import
An .NET example can be found here.
Jun
26
reviewed Close Solving non-linear ODE analytically in mathematica
Jun
26
reviewed Close Package Problem
Jun
26
reviewed Leave Closed Can we start a petition?
Jun
26
reviewed No Action Needed How to remove brackets from this list?
Jun
25
comment Using Simplify on a consistent system returns False
Shall we add the bugs tag?
Jun
25
reviewed Close Can somebody run this for me?
Jun
25
reviewed Close Symbolic matrix calculation
Jun
25
reviewed Close Limit of form 1 raised to infinity
Jun
24
reviewed No Action Needed Steady State Numerical Solution of Heat Diffusion Equation in 2D
Jun
24
comment How to properly interpret a seemingly contradictory result in Mathematica?
@jkuczm updated the answer
Jun
24
revised How to properly interpret a seemingly contradictory result in Mathematica?
deleted 1246 characters in body
Jun
24
comment How to change a point to circle in a Graphics expresion
@AisforAmbition, questions like your first can be easily answered using the built-in documentation. Just highlight '&' and press F1. You need the second hit (Function). As to your second question: This has to do with operator precedence. Precedence of -> is higher than & and the pure function Circle[#, .5] & needs to be protected from being read as (Point -> Circle[#, .5] )&. You can find the precedence table on the tutorial/OperatorInputForms page of the documentation.
Jun
24
reviewed Leave Open How can I solve an equation independent of a variable?
Jun
24
reviewed Reviewed How to Export a mixture distribution to .json file
Jun
24
revised How to Export a mixture distribution to .json file
deleted 8 characters in body
Jun
24
answered How to properly interpret a seemingly contradictory result in Mathematica?
Jun
24
comment How can I solve an equation independent of a variable?
I'm also not really sure what Artes meant with his comment. Your question was asked politely and formatted correctly. The only problem he may have had with your question is that it is pretty basic and is answered in the documentation. Take for instance the Solve documentation page and open the "Properties & Relations" section and you'll find the needed tip to solve your problem. The documentation is huge though, so we can't really demand that everyone has read everything and this info wasn't really prominently there.
Jun
24
comment Apply solution rules to new functions as parameters
Yes, but the problem is that g[1] etc are not part anymore of the plot equation. So, you end up with a fixed plot (after you have removed the erroneous comma in your plot command) that doesn't change anymore when the g's and h's are manipulated.