Pinguin Dirk
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 Mar 8 comment Cropping a Plot without rasterization Just using PlotRange is no option? Like: Plot[x^2, {x, -1, 1}, Frame -> True, PlotRange -> {{-1, 0.5}, Automatic}] Mar 5 comment Extracting function calls from an expression @PlaysDice: based on the example he gave I figured that the identifying pattern of the items to select is the head F. Thus my solution. But you are right, assuming he doesn't nest, it will work just as well. Mar 5 comment Slow evaluation of complicated Table I suggest also reading this one here: mathematica.stackexchange.com/questions/2639/… Mar 5 comment Extracting function calls from an expression @PlaysDice: well, assuming you want to retrieve the functions on the second but last level (and thus: not nested like func1[0,func2[1]]), you could e.g. use Cases[expr, _, {-2}]. Is that what you are looking for? Mar 4 comment Extracting function calls from an expression @PlaysDice: well, as long as you can make a pattern, it should work. Is there a concrete example you have in mind? (I would suggest not using capitals for that, as many of them are reserved (such as E, C, D,...) Mar 4 comment Extracting function calls from an expression I am glad you like it & I am kinda proud you take that as a start learning more about MMA (or whatever that language is called these days)! Don't accept to hastily, there might be other (maybe even nicer ways) to get what you like, you don't want to scare them away, do you? :) (and try to be active in here, that's how I learnt a lot!) Jan 30 comment More elegant/efficient solution to browse through an array sure, just kidding - one can only guess what he wants, at this point Jan 30 comment More elegant/efficient solution to browse through an array or ArrayPlot[array, ColorFunction -> "Rainbow"] for the more visual people out there :) Jan 27 comment Evaluate function from a table it has no way of knowing that the function is in x. Afaik, you have to either use Composition or else Replace (a.k.a. /.), as shown above. Sorry don't have the time to write full answer. Jan 27 comment Evaluate function from a table Not sure I understand (also looking at @bills answer). I try: either explicitly compose like for any "normal function", like ff = #^2 & and then ff[ff[x]] respectively: g=ff[ff[#]]& or use Composition explicitly Jan 27 comment Evaluate function from a table try: f[[1]] = #^2 &(you need a pure function for that, see documentation). Also: check out: ConstantArray[0, 4]:) (fwiw: alternatively: f[[1]] /. x -> 2, but I wouldnt recommend that) Jan 21 comment How to place a matrix under controls (sliders) in a Manipulate? not sure if I understand: if you use the following in place of your controls, is that what you want? Column[{Control@{{a, 1, "x-Richtung"}, -3, 3}, Control@{{b, 1, "y-Richtung"}, -3, 3}, Control@{{c, 1, "z-Richtung"}, -3, 3}, Dynamic@Style[{{a, 0, 0}, {0, b, 0}, {0, 0, c}} // MatrixForm, FontSize -> 18, FontColor -> Black, TextAlignment -> Left]}] Jan 21 comment neighbor swapping distance between two strings I think EditDistance is a bad choice here, for "EditDistance treats transposition as separate deletion and insertion operations", so: EditDistance["ac", "ca"] yields 2, whereas: "Damerau-Levenshtein distance counts transposition as a single operation" (yields 1) Jan 1 comment how to calculate with just double floating point precision you might want to use Chop (use 2nd argument to specify tolerance). Dec 20 comment How can I find the sum of the even digits of a number of all elements of a list? yes, here I have Dot>Mine>Boole>Trapproach in timings, for n=10^6 Dec 20 comment How can I find the sum of the even digits of a number of all elements of a list? nice one - I tried to keep it readable up to some point, as I currently have no time to comment really :) but I like Dot there! Dec 12 comment how to deal with so many digits in plot ticks @Kuba: thanks for the flowers :) I've recently been so inactive, I even forgot the answers I posted myself... good thing you are more active and have the overview of the community! Dec 11 comment How to plot contours on the faces of a cube this might be of interest: mathematica.stackexchange.com/questions/26749/… Nov 28 comment How to convert long integers in the expression into the products of their prime factors via Mathematica? ah ok, I wasn't aware of that syntax, my bad. You could modify fact accordingly. Let me know if you need any help & thanks for the feedback Nov 28 comment How to convert long integers in the expression into the products of their prime factors via Mathematica? @LCFactorization: please define what you'd like to obtain in the final step (this is not fully clear to me). Thanks