576 reputation
110
bio website msemac.redwoods.edu/~darnold/…
location Eureka, California
age
visits member for 4 months
seen May 3 at 18:33
stats profile views 102

May
12
awarded  Nice Question
Apr
19
asked Laurent series expansion
Apr
2
awarded  Enthusiast
Mar
31
asked Convergence and value of a complex power series
Mar
22
asked Manipulate fails with f[x]=x^k/(1+x^k)
Mar
22
asked Solve f'[x]==0 for x
Mar
15
asked How do I add a color bar to a 3D plot?
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
ImageSize->400 worked. Thanks.
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
The Manipulate example is outstanding. This really helps one explore properly the region. Is there a way to make the result a little larger? It's a little to small for my old eyes.
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
Although this extra link is amazing, I don't think it is a duplicate, because I am asking for a technique on how to "shade" the image of the region under the mapping $f(z)$.
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
The difficulty in this drawing is the fact that you will have to take the domain out to infinity in order to get the right shading of the image region under f[z]. I wonder if anyone has any thoughts or strategies on that. I try the following, but that fixes up the end a bit but messes up the beginning: f[z_] := (z + I)/(z - I); pp = ParametricPlot[{Re@#, Im@#} &@f[x + I y], {x, 0, 50}, {y, 0, 50}, PlotRange -> 2]
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
When one draw these types of plots, they can be very confusing at first glance. If you have some knowledge of what to expect beforehand, then you can sort of figure out what you are looking at. However, that's not really the case if you don't have advanced knowledge. One thing that would be helpful is if you could do a side-by-side plot, the first of z, the second of f[z]. If you could color the four borders of z in four different colors, then match the borders in f[z] with the same corresponding colors, that would be really helpful.
Mar
5
comment Image of first quadrant under $f(z)=(z+i)/(z-i)$
I believe the answer should be that everything in the upper half plane outside of the upper half of the unit circle should be shaded. I was able to more close approximate the answer with PlotRange->2.
Mar
4
asked Image of first quadrant under $f(z)=(z+i)/(z-i)$
Feb
18
asked Defining a Function, := versus =
Feb
18
comment Complex line integral
I'm afraid that the code above is far too advanced for me to understand, so I'm going to have to ask some questions and take some time to learn more Mathematica before I can understand this answer. Let me start with these questions: (1) What is the purpose of SyntaxInformation? (2) What does "LocalVariables" -> {"Plot", {3, 3}} accomplish? (3) I was able to try the ArgumentsPattern and watch what happens if you enter too few or too many arguments to the function, but may I ask what would "Arguments"->{_, __, ___} mean?
Feb
17
asked Complex line integral
Jan
20
comment Taking Log Transformation of unit circle using Presentations package
I think it is this. In the circle case, the ComplexMap[Log] takes Log of the center, Log of the radius, and just draws another circle with the results. Hence, Log[0] is the problem?
Jan
19
asked Taking Log Transformation of unit circle using Presentations package
Jan
19
comment Complex Region using Presentations Package
I finding this a very helpful introduction to the Complex part of the Presentations package: mathematica-journal.com/data/uploads/2011/10/EisenbergPark.pdf