Reputation
Next tag badge:
404/400 score
70/80 answers
Badges
8 98 186
Newest
 Nice Answer
Impact
~938k people reached

47s
revised Is plot polluting my context?
edited tags
45m
comment find the tangent at a homogenous point to a curve
Your given point does not satisfy the homogeneous equation you gave.
1h
revised find the tangent at a homogenous point to a curve
edited tags
1h
comment Plot is discontinuous (it shouldn't be)
Nono, I am on a borrowed computer again for today, @bel. :)
1h
comment How do I color Riemann integral rectangles using conditionals?
I'm confused... you seem to have switched left and right here.
2h
answered Plot is discontinuous (it shouldn't be)
2h
comment Matrix multiplication for higher dimensional matrices
Yes: don't use MatrixForm[]. Then, try again.
2h
answered Matrix multiplication for higher dimensional matrices
2h
answered How to speed up Colorize
3h
comment Implicitly defined compact complicated surface
Blah, it was the RegionFunction that I missed in my attempts. Nice work!
3h
revised How to reduce the InterpolatingFunction building overhead?
added 75 characters in body
3h
revised Define PolyLog so that positive reals evaluate on upper edge of branch cut
added 182 characters in body
3h
revised Define PolyLog so that positive reals evaluate on upper edge of branch cut
added 17 characters in body
3h
answered Are variables always assumed to be real in Jordan Decomposition?
4h
revised Savitzky-Golay Filter to smooth noisy data
finally!
4h
comment How do I color Riemann integral rectangles using conditionals?
In case OP might be confused: Marco chose to use the "midpoint" Riemann sum for his demonstration here, but it is not too hard to adapt this for the "left" (OP's) or "right" cases.
4h
comment Programming for matrix manipulation
ArrayFlatten[] is quite useful for your third step.
4h
comment How does Mathematica understand branchcuts of the complex logarithm?
Currently. Log[] is "continuous from above", because evaluating it at the branch cut gives a result with positive imaginary part. To get the corresponding function that is "continuous from below", we use -Log[1/z], as whuber demonstrated in another answer, where evaluating at the cut gives a result with negative imaginary part. (Sometimes you'll see the notation $\log(-x\pm i0)=\log\, x \pm i\pi$ denoting this choice of continuity.) I'm thinking your arg and log can use this additional flexibility. :)
8h
comment How do I color Riemann integral rectangles using conditionals?
You've searched this site for other implementations of Riemann integration? There have already been a number of questions on this.
9h
comment Expand a product of operators
Composition is not commutative; I would have expected f1[b x] in the result instead of what you have.