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Feb
10
comment Programmatic immersion of 2D surfaces in 3D
One possible approach: discrete the pre-glued 2D shape, treat the 3D embedding of the vertices as unknowns, and do something like this with the gluing treated as boundary conditions. Of course you don't necessarily want a minimal surface, so you'd have to minimize something like distortion instead of area. It would be a lot of work, to be sure.
Feb
8
comment Image3D does not give the distinctive blurry look, version 10 Linux
Just tested it, and yes, I get the blurry look on Linux with the gltest fix.
Feb
8
comment Image3D does not give the distinctive blurry look, version 10 Linux
I think Mathematica fails to detect graphics capabilities on Linux for some reason, lack of 3D antialiasing being another symptom. For me the solution that worked consistently (both for invoking mathematica from the command line and for starting it from a launcher) was to replace the gltest binary. I wonder if it'll fix your Image3D issues too (I haven't tried it out, but I see you also don't have anti-aliasing in your screenshots).
Feb
8
comment What does GLTest do and what are the consequences of it failing
In a pinch, echo -e '#!/bin/bash\necho "GLTest_OK"' > gltest; chmod a+x gltest will also do.
Feb
8
comment Cluster a signal into areas of equal intensity
Related: Weighted Voronoi Stippling
Feb
7
revised Generating convex polyhedron from face planes?
Chop[] call was fixed in the text but not in the final code
Feb
4
comment Color a single contour from a ListContourPlot3D using values from a list
You could also just use one of Mathematica's many nice built-in color schemes, like ColorData["StarryNightColors"][func[x, y, z]].
Feb
4
comment Color a single contour from a ListContourPlot3D using values from a list
If you have Mathematica 10.2 or higher, you could also try ListSliceDensityPlot3D.
Feb
3
awarded  Popular Question
Feb
3
comment How to make a contour shading like this
You should also look into DensityPlot.
Jan
29
comment Grayscale Morphology
@SjoerdC.deVries: What you're thinking of, and what Mathematica apparently implements, is a special case of grayscale morphology with flat kernels. One can certainly use nonflat kernels in principle.
Jan
21
comment Battery charge simulation not clipping properly as it iterates
Also worth pointing out that Which is an expression that returns a value, so you could do batterylevel[[i]] = Which[mink < next < maxk, next, next <= mink, mink, next >= maxk, maxk] if you didn't know about Clip.
Jan
20
comment Working with $X^2$, where $X$ has the uniform distribution in $[-b,b]$
The joint density will be hard to plot because its support $\{(x,x^2):-b\le x\le b\}$ is a one-dimensional subset of the plane.
Jan
15
comment Need VectorPlot to ignore centre of region
A circle of radius 0.2 is defined by x^2 + y^2 > 0.2^2, not x^2 + y^2 > 0.2.
Jan
14
comment Contour plot of the imaginary portion of a function given the real part is positive
In that case you have to think about what you want drawn in the region where the real part of both functions is positive.
Jan
13
comment Contour plot of the imaginary portion of a function given the real part is positive
ContourPlot[Im[x + I y - Log[x + I y]], {x, -6, 8}, {y, -6, 6}, RegionFunction -> Function[{x, y}, Re[x + I y - Log[x + I y]] > 0]]
Jan
13
comment Change Contour Plot Overlap Ordering
Apparently Mathematica always draws contours in increasing order of function value. The easiest solution I can think of is to plot the negative of the function, ContourPlot[-Sqrt[...], ..., Contours -> -list].
Jan
13
comment Contour plotting multiple curves
Works for me: i.stack.imgur.com/eoARJ.png (Mathematica 10.1)
Jan
13
revised 3D representation of a transcendental equation
deleted 13 characters in body
Jan
13
answered 3D representation of a transcendental equation