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| bio | website | |
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| location | ||
| age | ||
| visits | member for | 7 months |
| seen | Mar 29 at 15:52 | |
| stats | profile views | 41 |
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Jan 22 |
awarded | Custodian |
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Jan 22 |
reviewed | Approve suggested edit on About calculating Integrals |
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Jan 22 |
comment |
About calculating Integrals @ThiesHeidecke That is not what I wanted. Of course you can try to approximate the specular highlight by sampling a single point on the ray, but that was not the Intention |
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Jan 22 |
comment |
About calculating Integrals @swish oic. Too bad this is impossible. I will continue testing and try to find a solution, I will come back to this later. |
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Jan 22 |
comment |
About calculating Integrals @swish you said it would Integrate... I dont believe so. Mathematica does not find a Integral for $e^{-cos^{-1}(u^2)}$, The resulting function would be way more complicated... |
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Jan 22 |
awarded | Commentator |
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Jan 22 |
comment |
About calculating Integrals I will post this to Math.SE in the original form in order to get further assistance. This question is less Mathematica-oriented I fear |
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Jan 22 |
comment |
About calculating Integrals @swish In fact, I have already made such an optimization to get only the third coordinate of H to change. Originally, $H(u)=\overrightarrow{a}+(\overrightarrow{b}-\overrightarrow{a})*u-\overrightarrow{x} + \overrightarrow{v}$. We modified the coordinate system in a way that made $\overrightarrow{b}-\overrightarrow{a}={0,0,v}$. If we were to change the coordinate system to make $H(u)={0,0,u*v}$, we would have to inversely transform x,l,n,v in every "step" of integration, which would be almost impossible I fear. |
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Jan 22 |
comment |
About calculating Integrals @DanielLichtblau I will try this. However it will make integrating way harder, as there will be a few new variables? That makes simplifying not easier... |
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Jan 22 |
revised |
About calculating Integrals added 4 characters in body |
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Jan 22 |
comment |
About calculating Integrals @swish I am absolutely sure. This is an integral over specular lighting (Gauss Specular lighting) along a part of the z-axis. The formula is $e^{-\angle(H,L)^2}$ - I just realized I forgot the ^2 >_< |
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Jan 22 |
asked | About calculating Integrals |
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Dec 25 |
accepted | Preventing Numerical value from being evaluated |
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Dec 24 |
comment |
Solving an Integral equation I found my typo in the third try (I thought that would not work, because it instantly threw dozens of errors at me) How do I improve the precision? AccuracyGoal and PrecisionGoal do not change the output? |
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Dec 24 |
accepted | Solving an Integral equation |
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Dec 24 |
revised |
Solving an Integral equation added 214 characters in body |
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Dec 24 |
comment |
Solving an Integral equation Oh I tried something similar aswell... I got a bunch of Infinite Expression errors however? I will add that to the OP |
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Dec 24 |
asked | Solving an Integral equation |
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Dec 9 |
comment |
Solving/Reducing equations in $\mathbb{Z}/p\mathbb{Z}$ Reduce[ Mod[ 2^n - n, 10^k] == 0 && 10^(k-1) < n < 10^k, n, Integers] gives me the same error for k>=5. But in general, shouldnt this be evaluated almost immediately? |
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Dec 9 |
accepted | Solving/Reducing equations in $\mathbb{Z}/p\mathbb{Z}$ |
