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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 3 months |
| seen | 16 mins ago | |
| stats | profile views | 170 |
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May 21 |
awarded | Quorum |
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May 18 |
awarded | Nice Answer |
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May 18 |
comment |
How to peel the labels from marmalade jars using Mathematica? +1 This is a nice practical example of using Mathematica's image processing capabilities. They seem quite comprehensive, but I haven't seen them used much around here (and I find the built in help a bit lacking). |
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May 15 |
answered | Random Geometric Graphs |
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May 14 |
answered | Populating and storing a very large array in Mathematica |
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May 10 |
revised |
Finding a fit to a multi-dimensioned function Added example |
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May 9 |
comment |
Finding a fit to a multi-dimensioned function @DanielLichtblau Each variable depends on all the model parameters, so I end up with different parameter values for the different fits. |
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May 9 |
comment |
Finding a fit to a multi-dimensioned function Thanks. This is working well for my problem. FindFit[data /. {{a_, b_}, {p_, q_}} -> Sequence[{a, b, 0, p}, {a, b, 1, q}], model.{1 - s, s}, ...] |
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May 9 |
accepted | Finding a fit to a multi-dimensioned function |
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May 9 |
awarded | Nice Question |
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May 9 |
asked | Finding a fit to a multi-dimensioned function |
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May 8 |
comment |
Background Shading in Histogram3D There's no 2011 data in what I was using, it's just where it decides the bin should be. |
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May 7 |
comment |
Background Shading in Histogram3D @Jens It's what I get with that data. My version gives a histogram with a bin stretching from 2010 to 2011. |
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May 7 |
answered | Background Shading in Histogram3D |
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May 2 |
answered | Having the derivative be an operator |
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Apr 27 |
answered | How to properly plot a response of a transfer function in Mathematica? |
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Apr 25 |
comment |
Interlacing a single number into a long list There are several good solutions to your problem below, but as an aside about your question of how to generate a list, there are a couple of easy ways: ConstantArray[1997,70] or Table[1997,{70}]. |
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Apr 19 |
comment |
Reproducing nested loops using Map? Plus you could use Function[{user, target}, getRowsForUserAndTarget[user, target]] if you want to give your arguments names instead of #. |
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Apr 18 |
awarded | Commentator |
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Apr 18 |
comment |
BoxWhiskerChart too slow on big datasets, how to speed it up? Using PerformanceGoal -> "Speed" as an option to BoxWhiskerChart will stop the tooltips. |
