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| bio | website | |
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| location | ||
| age | ||
| visits | member for | 1 year, 3 months |
| seen | May 13 '12 at 20:29 | |
| stats | profile views | 34 |
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Mar 7 |
accepted | How to sum up subelements of a list of unknown length |
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Mar 7 |
accepted | How to Delete Elements from List1 appearing in List2? |
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Mar 7 |
asked | How to efficiently Append a result of an operation on each element of a list to itself |
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Mar 1 |
asked | Select/Delete with Sublist elements? |
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Feb 28 |
comment |
How to solve for an Z-Score of a T-Distribution? thank you for your help, both solutions work well, sometimes I feel like its very hard to compute with mathematica, the next time I think again its so convenient :P |
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Feb 28 |
revised |
How to solve for an Z-Score of a T-Distribution? deleted 2 characters in body |
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Feb 28 |
asked | How to solve for an Z-Score of a T-Distribution? |
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Feb 15 |
asked | How to sum up subelements of a list of unknown length |
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Feb 5 |
awarded | Nice Question |
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Feb 5 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values thank you for your explanation: I used the following values: testsample = {0., 1., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0.}; findLsts3[testsample, 4, 4] |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values thank you for the alternative solution! |
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Feb 4 |
awarded | Commentator |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values additionally, it does not cover cases of a lot of zeros. so far: {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0} returns too much lists with zero. probably one has to just remove all lists where Count[zeros]=length resultlist. Edit: It Just occurs for len=maxZeros (and len<maxZero which goes against logic anyway). |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values Thank you a lot. Could you give me a brief explanation of rangelst{{1,2},{3,3},{5,4},{7,10},{8,11}} and the (#[[2]] - #[[1]]) >= 0 &]? I'm stuck here at the momens :s.. thanks a lot! |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values The Result looks correct, the random selection considers all possible list? I will find it out but I have to retrace the code (which will take a moment :P). Thank you a lot for your support!! |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values @J.M. getSamples[data, fixlen, maxzero, n]; getsamples[testsample, 4,1]: Leads to: {3, 1, 0, 5} {1, 0, 5, 5} {0, 5, 5, 1} {5, 5, 1, 2} … {4, 1, 4, 3} {1, 4, 3, 0} {0, 4, 1, 4} This is needed because: I need to (mostly) unbiased draw a random set of 1 year data (thus I will afterwards randomly select 1 valid list, if the experiment contains one). Dublicates needed as every resulting list is subject to another time frame. |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values @ heike: the length is fixed to 251 data point, this corresponds to 1 event day + 250 workdays, thus 1 year. An adaption of your solution would be to generate sublist of every resultlist > 250 days, but because I'm working with a lot of data this might not be the fastest version. |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values unfortunately its true that this only gives me list with no zeros. But i have a limit of 10 zeroes because 1 missing element would make a lot of experiments useless, even though they are of good quality, see Heike's ansatz.. |
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Feb 4 |
awarded | Supporter |
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Feb 4 |
comment |
Check in a series if there exists adjacent values with less than a certain number of missing values thank you a lot for your answer. It's true I cannot use the previous answers as they only generate lists containing no zeros values. But I still have a Issue here: I'm working with time series: Thus I need to have the list {0,2,0,3} {2,5} too, as it correspond to different time data points. I will try to look trough the code, any Idea how to adjust? The Idea Behind: I will only need to Randomly pick 1 list of at least 250, but with a random date. Thus to not bias the statistics, I will need to have overlapping lists. |
