Gabriel Landi
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 Feb1 awarded Yearling Jan18 awarded Good Question Jan16 comment More efficient matrix-vector product @Jens Actually, I asked that question :) Jan15 revised More efficient matrix-vector product Added that $A$ is symmetric Jan15 comment More efficient matrix-vector product @rcollyer What exactly do you mean by generating in eigenspace: if $A = S \Lambda S^{-1}$ then I should do $Ax = S \Lambda S^{-1} x$? Also, I read your link on spherical components, but didn't really get how that would translate to the present problem. Again, thanks for the help. Jan15 comment More efficient matrix-vector product Hi all. Sorry for the delay in answering. Yes, $A$ will usually have full rank. It is also symmetric and has zero diagonal. But I don't know all the $x$'s in advance, so I need one dot product at a time. Thank you all for the support. Jan15 asked More efficient matrix-vector product Jan8 awarded Popular Question Dec8 comment Converting other C++ classes to MTensor in LibraryLink @halirutan Oh yeah! Very much :) Sep12 awarded Caucus Aug25 accepted Computing polynomial eigenvalues in Mathematica Aug25 comment Computing polynomial eigenvalues in Mathematica @J.M. Amazing answer. Thank you a lot. Aug24 awarded Nice Question Aug24 comment Computing polynomial eigenvalues in Mathematica @ruebenko the example above comes from solving Newtons law for a system of particles. Gotta think about more examples. :) Aug24 asked Computing polynomial eigenvalues in Mathematica Aug23 comment Odd behavior of GridGraph and DirectedEdges @DavidCarraher Thanks for the answer. I'll report it as a possible bug. I am not sure this is related, but GridGraph draws the graph differently from other graphs. Aug23 asked Odd behavior of GridGraph and DirectedEdges Aug16 accepted Mathematica + Numerical Recipes Aug16 accepted Circuit drawing in Mathematica Aug14 comment LeastSquare Solution for the Continuous Time Lyapunov Equation No. I saw that on the documentation for LyapunovSolve but I don't understand the Mathematics of e Kronecker product.