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16m
comment How I can count multiplications in an experssion?
@Mr.Wizard. Perhaps we can agree that this is a rather difficult question to deal with -- especially since there are not any asterisks at all in a Mathematica numerical expression as the kernel sees them. Are we not counting virtual stars in a symbolic sky with no star to guide us, but only a rather poor example to serve in its place. No wonder there is no agreement on the answer. And, please, don't take this guff I'm spouting seriously.
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revised How I can count multiplications in an experssion?
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comment How I can count multiplications in an experssion?
@Mr.Wizard. Well, your string munger gets 3 from 1/(b s^3) + 1/t^4 and mine gets 6. Which do you think would be the value the OP would expect?
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revised How I can count multiplications in an experssion?
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answered How I can count multiplications in an experssion?
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comment How I can count multiplications in an experssion?
Please do not post code in a image. We need code posted as properly formatted text. Please edit your question by replacing the image with properly formatted code. Use the {?) that appears at the top right of the editor panel to learn how to format.
5h
revised How I can count multiplications in an experssion?
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5h
comment How I can count multiplications in an experssion?
This does not work. Take a look at countTimes[a*b*c].
6h
comment How can I solve an integral equation with two unknowns?
I can not understand what you are asking. There is not integral equation in your code nor is a function g. Please clarify your intent.
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reviewed Reviewed How can I solve an integral equation with two unknowns?
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revised How can I solve an integral equation with two unknowns?
Routine clean-up
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reviewed Reviewed How I can count multiplications in an experssion?
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revised How I can count multiplications in an experssion?
Routine clean-up
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reviewed Leave Closed Better way to binarize an image
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revised Solution to heat equation with Neumann boundary conditions and lateral heat loss
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comment Solution to heat equation with Neumann boundary conditions and lateral heat loss
Your definition of u[x, 0] is definitely inconsistent with your other equations. Given your expression for u[x, 0], I get 1.67605 for Derivative[1, 0][u][0., 0] and 0.198103 for Derivative[1, 0][u][0.2, 0]. So the error message you are getting seems cogent, and your first task is to specify a consistent system of equations.
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revised Solution to heat equation with Neumann boundary conditions and lateral heat loss
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revised Better way to binarize an image
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reviewed Leave Closed creation a table from a default module
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revised Find a Fourier series from discrete data
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