Michael Wijaya

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bio	website	holdfirst.wordpress.com
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	1,262 reputation	bio	website	holdfirst.wordpress.com	visits	member for	1 year, 3 months
420 badges		location	United States		seen	May 17 at 19:29

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Jun 13	comment	Checking if the roots of a function are real You can try checking that the imaginary part is zero. We can get the list of roots using `x /. {ToRules[Reduce[LegendreP[6, x] == 0, x]]}`. Then we map `Im` to each root using `Map[Im,%]`, which gives `{0,0,0,0,0,0}`. This seems to suggest that the roots are real, but I am not 100% sure.
Jun 13	comment	Splitting a list @BrettChampion At one point I made a list of things I liked about Mathematica, and it included the fact that everything is an expression. Lisp popped up when I researched the roots of this feature. On a related note, that book really did teach me to write recursions! (Always ask null?, etc.)
Jun 13	answered	Splitting a list
Jun 12	awarded	Nice Question
Jun 10	revised	Implementing Central Symmetry Chose a better reference, more accurate definition of orthogonal group
Jun 10	comment	Wagner's trick to monitor FindRoot no longer works in Mathematica version 8 @AlexeyPopkov Thanks! Could you also include a link to the documentation where that "standard" trick is explained? I apologize for making so many requests of you.
Jun 9	comment	How to Clear a symbol with subscript in Mathematica? By the way, there is still one typo in your reply. You wrote `Unset[Subscript[[Lambda], 0]]`, which is missing a backslash.
Jun 9	comment	How to Clear a symbol with subscript in Mathematica? I started with a fresh Mathematica session. In that case, `Subscript[\[Lambda], 0] = 1` followed by `Unset[Subscript[\[Lambda], 0]]` does not generate any warning message. I can even do the assignment `Subscript[\[Lambda], 0] = 2` after that. If you just want to clear $\lambda_{0}$, you probably do not need to use the `Notation` package. Maybe you made the problem worse by calling functions from that package?
Jun 9	comment	How to Clear a symbol with subscript in Mathematica? Have you tried `Unset[Subscript[\[Lambda], 0]]` instead of `Unset[Subscript[Lambda, 0]]`?
Jun 9	accepted	Wagner's trick to monitor FindRoot no longer works in Mathematica version 8
Jun 9	comment	Implementing Central Symmetry Szabolcs' image uploader came in handy.
Jun 9	answered	Implementing Central Symmetry
Jun 9	comment	Wagner's trick to monitor FindRoot no longer works in Mathematica version 8 @AlbertRetey I am not sure I understand how that trick works in this context. Could you post an answer based on that?
Jun 9	comment	Can a function be made to accept a variable amount of inputs? +1 Your method is much cleaner than mine. It is good to know about `Check` too.
Jun 9	comment	Wagner's trick to monitor FindRoot no longer works in Mathematica version 8 `Evaluated` is not listed as one of the options for `FindRoot` in the documentation. What does it do?
Jun 9	comment	Implementing Central Symmetry By central symmetry, do you mean point reflection? If that is the case, you can use `ScalingTransform[{-1,-1,-1},{p1,p2,p3}]`. This will reflect your graphics object about the point $(p1,p2,p3)$. I assume you plan to use it for 3-dimensional graphics object.
Jun 9	comment	Can a function be made to accept a variable amount of inputs? @Mr.Wizard I mixed up two ideas when I wrote up the answer. The original function does not actually require the use of `BlankSequence`. In fact, it fails if I evaluate `datasetAverage[{1,2,3},{4,5,6}]`.
Jun 9	revised	Can a function be made to accept a variable amount of inputs? Replaced BlankSequence with Blank in the definition of datasetAverage
Jun 9	revised	Can a function be made to accept a variable amount of inputs? Replaced BlankSequence with Blank in the definition of datasetAverage
Jun 9	comment	Can a function be made to accept a variable amount of inputs? You may want to wait for other answers before accepting. I am sure the regulars here can offer more refined answers.