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Dec
30
comment Position from 3 dimensional acceleration data?
As @DanielLichtblau pointed out, it's not clear what problem you've identified. That said, what you're trying to do is tricky, at best. Since you're doubly integrating accelerometer data, biases become a major error source (the bias is the value that the sensor indicates when it's not accelerating). Furthermore, biases drift, so correcting for them is challenging. Add to that noise and other error sources, and you've got a tough problem. Finally, you need to correct for the rotational motion of the earth...
Nov
10
awarded  Good Question
Sep
26
awarded  Popular Question
Aug
3
reviewed Reject Deleting all characters in a string that do not belong to a small set of elements
Jul
20
reviewed Approve ParallelSum in Mathematica 9 vs 10
Jul
2
awarded  Curious
Jun
15
reviewed Edit On Parameter Estimation using FindDistributionParameters
Jun
15
revised On Parameter Estimation using FindDistributionParameters
improved question
Jun
15
reviewed Approve How to eliminate the need to double evaluate a Manipulate so that a Module in its Initialization section works?
Jun
15
reviewed Approve PlotLabel moves, when i rotate my 3D graphic
Jun
15
reviewed Approve How To interactively create a Polygon in a Graphic?
Jun
15
reviewed Approve Manipulate fails with f[x]=x^k/(1+x^k)
Jun
5
reviewed Approve Rewriting one expression using a variable representing another expression
Jun
5
reviewed Approve Numerical vs Symbolic Integration: Loss of precision
Jun
4
comment Switching the ordinate and abscissa causes problem in `ParametricPlot`
It worked because your list effectively requested two parametric plots (new[x] and x), though the second parametric plot was underspecified and thus ignored by MMA.
Jun
4
answered Switching the ordinate and abscissa causes problem in `ParametricPlot`
Jun
4
revised Making a Mathematica package manager?
Fixed minor typo
Jun
4
answered How to calculate this integral?
Jun
4
comment How to calculate this integral?
I'm also unable to get MMA to calculate the integral symbolically. However, you can calculate it numerically for a given value of a: NIntegrate[(Exp[-a x] (x^2 - 1)^(13/2)/x^10) /. {a -> 0.1}, {x, 1, [Infinity]}]
Jun
3
comment How to compute this triple integral?
Heh. Sometimes it's better to be lucky than to be smart!