125 reputation
4
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location Krakow, Poland
age 23
visits member for 7 months
seen May 7 at 16:33
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May
7
accepted Why is arithmetic faster for inexact arithmetic?
May
7
comment Why is arithmetic faster for inexact arithmetic?
Thank you! This clarifies a lot.
May
7
asked Why is arithmetic faster for inexact arithmetic?
Apr
29
comment Exploiting self-adjointness when changing basis
Thank you, that was just what I needed. And yes, I did mean $Q' = P^{-1} Q P$; just corrected it for increased readibility.
Apr
29
awarded  Scholar
Apr
29
revised Exploiting self-adjointness when changing basis
edited body
Apr
29
accepted Exploiting self-adjointness when changing basis
Apr
29
awarded  Student
Apr
29
awarded  Editor
Apr
29
revised Exploiting self-adjointness when changing basis
edited title
Apr
29
asked Exploiting self-adjointness when changing basis
Oct
1
awarded  Supporter