| bio | website | uoregon.edu/~noeckel |
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| location | ||
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| visits | member for | 1 year, 3 months |
| seen | 4 mins ago | |
| stats | profile views | 1,323 |
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Apr 18 |
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Obtaining a conic sections by slicing a cone possible duplicate of Manipulate - why does the axis scale change when I release the slider? |
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Apr 16 |
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How do I simplify a vector expression? I already anticipated this comment in my answer, and mentioned that it opens up a wide field of additional definitions one could add. I may come back to that when I have time. |
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Apr 15 |
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Symbolic evaluation fails because it exceeds $RecursionLimit Yes, that's a way around the problem (+1). And if you have other cases where Subscript needs its arguments evaluated, you just have to wrap those in Evaluate. |
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Apr 14 |
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Series expansion in terms of Hermite polynomials @belisarius For that general case, at least I can allow a larger basis than necessary, with the latest edit. Then basis can be kept fixed as some list with a number of polynomials that is expected to be large enough for all purposes. |
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Apr 14 |
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Series expansion in terms of Hermite polynomials @belisarius That's what my second version does. Or are you referring to the case of a more general basis? |
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Apr 14 |
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Series expansion in terms of Hermite polynomials @belisarius See edit - I hardcoded the HermiteH part into the function in case you're only interested in those basis functions. Then the counting of terms is automatic. In the first version, I wanted to keep the list basis deliberately general so you can use other polynomials there, too. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? Maybe you have time to try the OP's new original code. I can't do it right now. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? The edit contains various syntax errors. Definitions like f[u] should be f[u_], spaces are missing between names. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? I was working in version 8 when I wrote my answer so I couldn't go this route, but I agree this is a nice new feature (+1). |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? I can't execute your edited new code, but the fact that you get the quoted error message means that you probably did everything right up to the point of finding $\omega$. The issue you're seeing now is unrelated to the original one. There's a lack of precision in calculating the NDSolve solution, or maybe the zero is not where you think it is. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? @Spawn1701D I'm just taking the question as stated: "an analogous problem is..." so we have a linear second order BVP. Then of course you can't use the initial derivative as the parameter. It's simply an eigenvalue problem, and you shoot for the value of $\omega$ that satisfies the BC. My guess is that you're reading too much into the question. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? @Spawn1701D The initial condition is $p'[0]=1$, and that's a standard choice which doesn't require knowing the solution. It's just selecting the non-trivial solution consistent with the boundary condition at $0$. The other linearly independent solution is $p[0]=1$, $p'[0]=0$; this is always true for such equations. Basically what I'm doing is a shooting method that converts the BVP into an initial value problem. I'm sure that's what Paul is doing, and that's why FindRoot comes in. |
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Apr 13 |
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How can I use FindRoot on an expression from NDSolve? @Spawn1701D The fact that his example has a trivial solution doesn't mean that the example is trivial. It has a non-trivial solution too (any linear homogeneous equation has a trivial solution, but nobody cares). How to obtain the latter using NDSolve is a valid question, which I answered. |
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Apr 12 |
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Dynamic visualization of Graph[] on a webpage Since this can't even be done in Mathematica, I think an equally valid question would to be: how to implement the dynamic rearrangement of vertices in Mathematica, so that it can potentially be exported as a CDF. I'm not saying I would do that, though. I like the SVG + JS approach in your self-answer too. |
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Apr 11 |
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Area of the largest rectangle bounded by $y=x^2$ and the x-axis within the unit interval In a situation where you're not sure how to begin, it's usually best to try doing it by hand instead of jumping straight into Mathematica. |
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Apr 10 |
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StreamPlot in Polar Coordinates It works (+1), but I had to correct a small syntax error in StreamScale where a } is missing. |
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Apr 10 |
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StreamPlot in Polar Coordinates Oh yes, I overlooked that part. I'll edit my answer to fix it usng the same method I used here. |
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Apr 9 |
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Composing an image with a plot The answers with Manipulate reminded me of this question: Animate ParametricPlot3D for two different parametric equations |
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Apr 9 |
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How to label vertices in a grid with random integers? It would be best if you post some code that you have tried so that readers can get a better idea of where your Mathematica problem is. |
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Apr 8 |
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Integral evaluation taking too long @NoLeafClover Of course I can't really guess what your goal is. But the step functions have no effect for s > t, and the remaining terms don't go to zero, so the infinite integral goes to infinity. |