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May
10
comment Can I open Mathematica to plot something via some kind of Windows command?
Sure, but I actually think gnuplot is much better suited for batch jobs like this, and in many cases its output also looks more professional than Mathematica. I don't like having to say that, but it's a fact.
May
10
comment Can I open Mathematica to plot something via some kind of Windows command?
No, that's not possible directly because the command syntax for gnuplot as contained in the parameters p1 etc. is completely different from Mathematica, and you'd first have to write a converter from gnuplot to Mathematica. gnuplot syntax is in turn similar to Matlab syntax, but that doesn't guarantee that a translation would be straightforward.
May
9
comment Arrowheads not quite working as expected
This also happens in version8, so I'll remove the version-10 tag. I think it's a bug.
May
9
comment How can I force the assumption that a symbol is a vector of n zeros
@m_goldberg Ah, thanks for clarifying that. I think the question needs clarification because the motivation for starting with that particular assumption is not given. That could help find a useful answer even if Norm as an assumption doesn't work so directly.
May
9
comment How can I force the assumption that a symbol is a vector of n zeros
@m_goldberg I think that assumption is strictly true. The norm is zero iff the vector is zero. But Refine simply doesn't use the norm.
May
7
comment Fundamental question about capabilities of Mathematica to represent abstract mathematics
Have you looked at the documentation for Resolve and Reduce? You can certainly derive other statements from given expressions. So the answer to question 2. seems to be yes, and that makes the other points of the question moot. But as to your first points, you'll have to do some work to bring your statements into the form of Mathematica expressions. It would certainly be appropriate as a question, but I think you would need to show some example of what you have already tried to make this question less ambiguous. As is, it's not easy to parse by a human, let alone a program.
May
6
comment FullSimplify wrongly reduces expression to zero
In version 8, the first line with FullSimplify stays unevaluated, so the result is the same as for Simplify.
May
5
comment Animated Wave propagation using split operator method
As I said, it's an arbitrary choice, you can change it to whatever you need. There's nothing more to it.
May
5
comment Animated Wave propagation using split operator method
You can put in any parameters you like. It depends on the physical constants of your problem, such as Fermi velocity etc. But choosing the numerical values of the constants in the equation is not a Mathematica issue.
May
5
comment Solving a vector equation
@Guesswhoitis. That's what I did in the answer of which this is a duplicate...
May
4
comment Animated Wave propagation using split operator method
Yes, you're right - that was intentional. Such prefactors aren't important in linear differential equations, but of course they do affect your normalization integral. Since the question asked for a plot, I left out the prefactor because it doesn't affect the displayed shape.
May
4
comment Animated Wave propagation using split operator method
You can't make a plot of that because there are no more variables to vary when you integrate. Also, the integration has to be within the NDSolve domain.
May
4
comment Animated Wave propagation using split operator method
The 2 is added and subtracted only to offset the 3D plots vertically, so you can see them better. You can change the plot to Plot3D[ Abs[\[CapitalPsi]1[x,y,t]]^2+Abs[\[CapitalPsi]2[x,y,t]]^2, ... and that will produce the modulus squared. For more information on the styling, also have a look at the options of the Plot3D command.
May
4
comment Animated Wave propagation using split operator method
The formulation of the problem is incorrect. The matrices are infinite-dimensional either in real or Fourier space and need truncation. You can't get the time evolution of a spinor with position dependence by just using 2D matrix multiplication. The main issue here is unrelated to Mathematica.
May
1
comment DifferentialRoot
As I commented below the answer from which this question is derived, what you're getting is a solution in the form of a function that has to be numerically evaluated. Not every differential equation can be solved in terms of named special functions. Maybe if you make additional assumptions about boundary conditions you could get a simplification, in particular if you put those boundary conditions in to DSolve from the start. But as it stands, there's probably nothing better available within Mathematica. Provide all known assumptions.
May
1
comment Solving differential equation
Yes, my first approach does yield a solution in the form of a DifferentialRoot, which means you have a solution but it can't be expressed in terms of special functions. So you then have a solution for ySolution that can only be evaluated when you give numerical values to the parameters. The integration constants in that DifferentialRoot can in principle also be eliminated by adding two boundary conditions to eqn2, e.g. like this: DSolve[eqn2&&z[1]==1&&z'[1]==1,z[v],v]. The result still needs a numerical value for $\lambda$, though.
Apr
30
comment Arrowhead becomes unattached to line in a Graphics3D Manipulate
Possibly related: Why does Arrow not work well with Scaled coordinates in 3D?. I don't see this issue in version 8, but the work-around in the linked question may be of interest here, too.
Apr
30
comment How do I draw a polygon defined by a list of data points?
Based on the description, it seems the starting point was a binary image. In that case, this could be a duplicate of, or at least closely related to, How to extrude a 3D image from a binary 2D image
Apr
28
comment Can Mathematica produce manipulatable 3D plots for deployment on the web?
WebGL is not an export format but, as the Wikipedia link states, a JavaScript API. You can use it to implement viewers for the export formats that Mathematica supports. There already are many such viewers. E.g. VRML has been around for so long that you can easily find viewers with Google. Then there are solutions based on three.js - but with all those options it's hard to know what kind of answer you're really looking for. Too many options... maybe look into processing.js, it's easy to learn and can load 3D graphics.
Apr
28
comment Animation of double pendulum
@SebastianHenckel That's correct - if you want the movie to run at the actual speed of the motion, you have to play with the fps and duration. If you have a suggestion for how best to do it, I can add it.