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May
2
comment Polar Plotting in Complex Plane
This set of functions is so simple that I'm guessing you should really try to do it by hand to gain some understanding first. Alternatively, if you have already tried something in Mathematica and aren't happy with it, please post your attempt so it becomes clearer where your difficulties lie.
May
1
comment To solve Cylinderical PDE
@Umer By the way, I also implemented a relaxation method for this kind of problem in Poisson solver using Mathematica.
May
1
comment To solve Cylinderical PDE
@Umer Yes, that is a possible numerical approach that should work for you too. But he also clearly says that it's not the first choice of approach. Even the method of lines can in principle be used if you add another step that varies the initial conditions until the final conditions are met. But all these approaches are "band-aids." In your case, since it's analytically solvable I would maintain that that's the way to go.
May
1
awarded  Enlightened
May
1
comment To solve Cylinderical PDE
@chris yes - the number of coordinate systems is finite (and they're already built in), but actually here we don't even need to go that far because the coordinates have already been chosen and it's just about identifying the separation step.
May
1
comment To solve Cylinderical PDE
@Umer The problem is that you require boundary conditions on both ends of both intervals for your variables. The method of lines works only when you pose initial conditions, it doesn't know how to aim for the correct final condition.
May
1
comment To solve Cylinderical PDE
@chris That may be possible - although in general it may need more steps to insure that Mathematica multiplies by the correct powers of the independent variables to get the equivalent of pde2. I did manage to make it work in parabolic cylinder coordinates, so maybe I'll post an expanded version later.
May
1
awarded  Nice Answer
May
1
revised To solve Cylinderical PDE
typo
May
1
answered To solve Cylinderical PDE
May
1
awarded  Revival
Apr
30
comment Changing size and color of a Text on version 9
@Kuba OK, done.
Apr
30
answered Changing size and color of a Text on version 9
Apr
30
comment Alternative for citation management in Mathematica 9 for Mac
You've probably seen this: Where is the “Insert > Citation> Bibliographical Reference” Command?. I recommend using LyX if you need BibTeX integration and want excellent math typesetting.
Apr
29
comment A question about definite integrals and timing
Closely related: What exactly does GenerateConditions do?
Apr
29
answered ComplexExpand absolute squared
Apr
28
comment add a legend show the expression for each contour?
@qed Are you using Mathematica version 8? Then maybe you can use the solution to Creating legends for plots with multiple lines: Copy the first code block and then do this: autoLegend[cc,{Abs[x]^(1/2)+Abs[y]^(1/2)==1,Abs[x]+Abs[y]==1,Abs[x]^2+Abs[y]^2=‌​=1,Abs[x]^3+Abs[y]^3==1},Alignment->{.1,Center}] where cc is your ContourPlot.
Apr
28
comment Mesh and ParametricPlot
yes, that sounds like the best route. eschew Show... Gesundheit.
Apr
28
comment Mesh and ParametricPlot
So you are agreeing with what @cormullion essentially observed, too. The problem with changing the order of presentation in Show is that the purpose of setting Opacity in the first place was so that it can be placed on top of a Graphics that comes before the RegionPlot. So changing the order doesn't really seem to be a solution.
Apr
27
answered Why does Mathematica not replace the derivative of $theta$1'[t]?