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May
4
comment Animated Wave propagation using split operator method
The formulation of the problem is incorrect. The matrices are infinite-dimensional either in real or Fourier space and need truncation. You can't get the time evolution of a spinor with position dependence by just using 2D matrix multiplication. The main issue here is unrelated to Mathematica.
May
3
answered How to plot a finite number of vectors?
May
3
answered Overlapping Spheres with a Shared Blank Region
May
2
reviewed Close Calculate the total length of line segments within polygon
May
2
reviewed Close Division binary using polynomials
May
2
reviewed Close Solve system of equations with implicit function
May
2
reviewed Close NIntegrate producing SetDelayed::write message
May
1
revised DifferentialRoot
replaced unreadable output by image
May
1
comment DifferentialRoot
As I commented below the answer from which this question is derived, what you're getting is a solution in the form of a function that has to be numerically evaluated. Not every differential equation can be solved in terms of named special functions. Maybe if you make additional assumptions about boundary conditions you could get a simplification, in particular if you put those boundary conditions in to DSolve from the start. But as it stands, there's probably nothing better available within Mathematica. Provide all known assumptions.
May
1
comment Solving differential equation
Yes, my first approach does yield a solution in the form of a DifferentialRoot, which means you have a solution but it can't be expressed in terms of special functions. So you then have a solution for ySolution that can only be evaluated when you give numerical values to the parameters. The integration constants in that DifferentialRoot can in principle also be eliminated by adding two boundary conditions to eqn2, e.g. like this: DSolve[eqn2&&z[1]==1&&z'[1]==1,z[v],v]. The result still needs a numerical value for $\lambda$, though.
May
1
reviewed Close Graph Edit Distance with Mathematica?
Apr
30
comment Arrowhead becomes unattached to line in a Graphics3D Manipulate
Possibly related: Why does Arrow not work well with Scaled coordinates in 3D?. I don't see this issue in version 8, but the work-around in the linked question may be of interest here, too.
Apr
30
revised How do I draw a polygon defined by a list of data points?
Discussed better choice of VertexNormals
Apr
30
awarded  Nice Answer
Apr
30
comment How do I draw a polygon defined by a list of data points?
Based on the description, it seems the starting point was a binary image. In that case, this could be a duplicate of, or at least closely related to, How to extrude a 3D image from a binary 2D image
Apr
30
answered How do I draw a polygon defined by a list of data points?
Apr
29
reviewed Close Issue when using Ticks and Frame
Apr
29
reviewed Close Incompatibility of Append and NumberForm?
Apr
29
reviewed Close accessing solution of pde
Apr
28
comment Can Mathematica produce manipulatable 3D plots for deployment on the web?
WebGL is not an export format but, as the Wikipedia link states, a JavaScript API. You can use it to implement viewers for the export formats that Mathematica supports. There already are many such viewers. E.g. VRML has been around for so long that you can easily find viewers with Google. Then there are solutions based on three.js - but with all those options it's hard to know what kind of answer you're really looking for. Too many options... maybe look into processing.js, it's easy to learn and can load 3D graphics.