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Jul
22
revised HoldForm doesn't hold form
Version info updated
Jul
22
comment HoldForm doesn't hold form
What you observed also holds for Hold in the same context, so you must have hit the nail on the head. I think this cannot have been done intentionally - it makes no sense.
Jul
22
comment HoldForm doesn't hold form
I suspected that one could find a working character encoding, but of course I would like to keep the default encoding. Anyway, thanks for that find, too! In terms of using Inactive[Set], I would then probably not bother and rewrite everything with FormBoxes. But the fact that Hold has the same issue as HoldForm in AxesLabel really worries me.
Jul
22
comment HoldForm doesn't hold form
That's a valuable observation, thanks!
Jul
22
comment HoldForm doesn't hold form
@m_goldberg Will do. There are no change notes for HoldForm in the docs, so I would think this is a regression.
Jul
22
comment HoldForm doesn't hold form
Thanks, that's definitely a workaround in some cases. But unfortunately it doesn't solve the issue with my first Plot example, where I used the (admittedly contrived) label HoldForm[InputForm[E = 1]] to get E instead of the double-struck letter.
Jul
22
revised HoldForm doesn't hold form
deleted 1 character in body
Jul
21
asked HoldForm doesn't hold form
Jul
21
comment Using a function name instead of its definition in AxesLabel
@BenAllgeier I also see this problem, and I think it's a bug in version 10. I'm currently mostly using version 8 because I want to wait until the bugs are fixed. In the meantime, maybe you can instead use my answer here, until we figure out what's wrong with HoldForm. I'll update this when I know more...
Jul
21
reviewed Close How to get the indices of an Image3D that have a value of interest
Jul
20
comment Checking Calogero-Moser eigenfunction
The question has been cross-posted at MathOverflow.
Jul
20
comment How to enter chemical equations?
Perhaps this Scientific American article is of interest. If you do want fast note taking, I would recommend LyX.
Jul
20
comment Checking Calogero-Moser eigenfunction
The sums aren't infinite, they are limited by the quantum numbers p, q, r. Anyway, I don't know a quick answer because I'd have to define your Hamiltonian first. The trick I use in the linked answer relies on Solve to do some of the work of simplifying and isolating the eigenvalue, which in general works much better than the naive approach of dividing HJ by J. But even this approach may fail for really complicated expressions like yours, unfortunately.
Jul
20
comment Checking Calogero-Moser eigenfunction
The general problem of solving for an eigenvalue of an operator (knowing that you have an eigenfunction) is addressed e.g. in my answer to this question: Operator operation
Jul
19
comment Collapsing summation
In addition to the question @mfvonh asked, you should also specify what to do with cases like F[1,i]+F[2,i]+F[3,i] where i would appear as the summation index and as an external variable. That doesn't look like a replacement I would want to make in general. The answer would probably use UpSetDelayed, not unprotecting Plus.
Jul
19
reviewed Close LegendLayout not working as asked
Jul
19
reviewed Close A problem about function N
Jul
19
reviewed Close Calculating Muliti-integral Time-Ordering operator
Jul
18
reviewed Close NIntegrate with a parameter in integrand and upper limit
Jul
18
reviewed Close Game of Life in 3D