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Oct
4
revised xkcd-style graphs
added 177 characters in body
Oct
3
comment FindRoot on a 2D list of Equations
@MarkMcClure oh wow. MapThread does exactly what I wanted. Thanks a lot.
Oct
3
comment FindRoot on a 2D list of Equations
@belisarius ... I wonder what's the over/under on a 100k views on this post.
Oct
3
comment FindRoot on a 2D list of Equations
@J.M. It works either way.
Oct
3
comment FindRoot on a 2D list of Equations
@belisarius lol..
Oct
3
asked FindRoot on a 2D list of Equations
Oct
2
comment xkcd-style graphs
@FredrikD I tweeted the link to him.
Oct
2
comment FindRoot inside Table
can you please tell me how to extend this command eqs = (# == 0) & /@ (rhs/scale); to the case where rhs/scale is a 2 dimensional list. Thanks. If rhs/scale = {{y,y1},{z,z1}} then right now I am getting {{y,y1}==0,{z,z1}==0} but I would like to get {{y==0,y1==0},{z==0,z1==0}}. Thanks.
Oct
2
awarded  Stellar Question
Oct
1
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Oct
1
comment xkcd-style graphs
Fantastic answer Simon. The Fonts look amazing!
Oct
1
comment xkcd-style graphs
Oh This is beautiful Chris! @Mr. Wizard, belisarius and others, should I wait for a couple of days before accepting an answer so more people can attempt refinements or not since Chris has pretty much nailed the problem.
Oct
1
awarded  Famous Question
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1
awarded  Good Question
Oct
1
awarded  Nice Question
Oct
1
asked xkcd-style graphs