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Oct
9
comment Learning Finance with Mathematica
@GeorgeWolfe The Why is critical to this whole enterprise. Someone with a strong Statistics, Econometrics and programming background will not go very far if they don't understand the Finance and Economics behind the models. Your road-map is absolutely essential to keep OP's project from being DOA. Presumably some of those MMA for Fin-engineering books will provide some of this perspective but I am not optimistic about the quality.
Oct
9
asked Exporting data to a new excel sheet of a pre-existing excel file
Oct
7
asked saving Manipulate data inside a notebook
Oct
6
accepted xkcd-style graphs
Oct
6
revised xkcd-style graphs
added 180 characters in body
Oct
5
accepted Manipulate indexed Interpolating Functions
Oct
4
revised Manipulate indexed Interpolating Functions
added 866 characters in body
Oct
4
comment Manipulate indexed Interpolating Functions
Hey rm-rf, thanks for your answer. I tried working with it and it worked. I'll posted the working verison below in the question. The trick was to index the data and calculate a fresh interpolation inside the Manipulate, as opposed to indexing the interpolation function.
Oct
4
revised Manipulate indexed Interpolating Functions
deleted 1017 characters in body; edited title
Oct
4
comment Manipulate indexed Interpolating Functions
Thanks, I'll post data in a sec and also try your method. The problem with me is that my interpolating functions look like ifun[gamma][x] where gamma $\in \{1,100\}$. I'll post a MWE in a few minutes.
Oct
4
asked Manipulate indexed Interpolating Functions
Oct
4
accepted FindRoot on a 2D list of Equations
Oct
4
revised xkcd-style graphs
added 177 characters in body
Oct
3
comment FindRoot on a 2D list of Equations
@MarkMcClure oh wow. MapThread does exactly what I wanted. Thanks a lot.
Oct
3
comment FindRoot on a 2D list of Equations
@belisarius ... I wonder what's the over/under on a 100k views on this post.
Oct
3
comment FindRoot on a 2D list of Equations
@J.M. It works either way.
Oct
3
comment FindRoot on a 2D list of Equations
@belisarius lol..
Oct
3
asked FindRoot on a 2D list of Equations
Oct
2
comment xkcd-style graphs
@FredrikD I tweeted the link to him.
Oct
2
comment FindRoot inside Table
can you please tell me how to extend this command eqs = (# == 0) & /@ (rhs/scale); to the case where rhs/scale is a 2 dimensional list. Thanks. If rhs/scale = {{y,y1},{z,z1}} then right now I am getting {{y,y1}==0,{z,z1}==0} but I would like to get {{y==0,y1==0},{z==0,z1==0}}. Thanks.