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Code for my breathing avatar here


You may contact me at: BelisariusForSO@gmail.com

But please don't email me with requests about Q&A. Post them in the site instead.

Infix should be used only where it is essential... like in "feliz año nuevo" @rm-rf


Jan
30
revised Transforming an image as an object
added 121 characters in body
Jan
30
comment Define a function on a parameter argument set to zero
So I suggest you to edit your question accordingly
Jan
30
comment Define a function on a parameter argument set to zero
It happens! no problem!
Jan
30
comment Transforming an image as an object
@YvesKlett Just a standard third world inet uplink
Jan
30
comment Transforming an image as an object
@YvesKlett uploading ...
Jan
30
answered Transforming an image as an object
Jan
30
revised Transforming an image as an object
deleted 15 characters in body
Jan
30
comment Define a function on a parameter argument set to zero
Perhaps you need ClearAll[m] ?
Jan
30
comment Define a function on a parameter argument set to zero
m[var_] := f - (f /. var :> 0); m[a] == f - (f /. a -> 0)
Jan
30
comment More elegant/efficient solution to browse through an array
list = Permutations@Range@3; Correlation @@@ Subsets[list, {2}] ?
Jan
30
comment More elegant/efficient solution to browse through an array
@holistic Mathematica has a lot of ways to do that kind of things. If you edit your question and post a few examples of your needs I'm sure you'll get more specific answers. Mr.Wiz here interpreted "browsing" as "looking at", as most of us did
Jan
30
revised Isolating characters in a string
deleted 13 characters in body
Jan
30
answered Isolating characters in a string
Jan
30
comment DSolve cannot solve for certain branches of the solution help pls
a) There is a missing comma after your third equation b) Don't start your symbols with uppercase letters c) C is a system-defined symbol d) DSolve[] doesn't seem able to solve that system
Jan
30
revised DSolve cannot solve for certain branches of the solution help pls
deleted 65 characters in body
Jan
30
comment How to obtain the number of Markov Chain transitions in a simulation?
Tally@Partition[data["Path"][[All, 2]], 2, 1]?
Jan
30
comment Isolating characters in a string
Identifying problems is quite different from having solutions :)
Jan
30
comment Isolating characters in a string
The problems with this kind of approach are that 1) y gets evaluated, which is an undesirable side effect and also, 2) if the xn already have assigned values in the .nb it fails. That's why I posted my "solutions" as comments in the question
Jan
30
comment Isolating characters in a string
Coefficient[#, Variables@#] &@ToExpression[str] ... etc
Jan
30
comment Isolating characters in a string
CoefficientRules[#, Variables@#] &@ToExpression[str]