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 21h comment How to extract a region shape from an 2 colour image? @Edmund Of course. I made up that because I found corner cases where FilliTransform wasn't enough. Trying to remember what were those :) 1d revised How to evaluate the limit of a function consists of Range added 64 characters in body 1d revised How to evaluate the limit of a function consists of Range deleted 21 characters in body 1d comment How to evaluate the limit of a function consists of Range @robit You can find more info on the convergence of those series here ... those problems were Ramanujan's pets 1d comment How to evaluate the limit of a function consists of Range @robit Well, it's the Kasner number. See this. 1d answered How to evaluate the limit of a function consists of Range 1d revised How to extract a region shape from an 2 colour image? added 529 characters in body 1d revised How to extract a region shape from an 2 colour image? added 2 characters in body 1d revised How to extract a region shape from an 2 colour image? added 555 characters in body 1d revised How to extract a region shape from an 2 colour image? added 37 characters in body 1d answered How to extract a region shape from an 2 colour image? 1d comment How to extract a region shape from an 2 colour image? The intersection? Are you sure? It will be very difficult to calculate the intersection of two shapes that aren't completely specified (in the general case, I mean) 1d comment Numerical Integration w/parameter 1d comment How to terminate early a functional computation @MikeHoneychurch Thanks a lot! 1d comment How to terminate early a functional computation I'm on V9- Could you please compare this with my cheap solution on the comments? I guess this one is faster, but I'm curious about the improvement 1d comment How to terminate early a functional computation @march Don't trust too much :) 1d comment How to terminate early a functional computation @march I was looking for a good example stackoverflow.com/a/6209778/353410 1d comment How to terminate early a functional computation Not very efficient a = {1, 2, 3, 4}; b = {2, 3, 4}; MatchQ[a, {___, PatternSequence @@ b, ___}] A Boyer-Moore type alg should be better 1d comment Give a common denominator to a whole list The real problem is how to get that numbers printed.Mathematica will simplify them on the fly. There are several related question to this on this site. Search for them 1d comment Specify only one jump direction of LocatorPane @Algohi I don't get you ...