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comment Factoring polynomials to factors involving complex coefficients
Yes it did, thank you.
Jul
12
accepted Factoring polynomials to factors involving complex coefficients
Jul
12
comment Factoring polynomials to factors involving complex coefficients
This may be too far beyond the scope of my original question (or this site for that matter) but why isn't it possible? It's not that I don't believe you, I'm just curious.
Jul
12
revised Factoring polynomials to factors involving complex coefficients
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Jul
12
comment Factoring polynomials to factors involving complex coefficients
As well is it simply not possible to tell mathematica to factor over the set of complex numbers rather then just the rationals + some specific given algebraic numbers? Or does this lead into issues with Non-Computable Transcendental Numbers? If so I should think it would be possible to simply factor over all Computable Algebraic Numbers (given enough computing power of course).
Jul
12
comment Factoring polynomials to factors involving complex coefficients
Thanks, but that is not the output form I'm looking for (See the comment on the original post). I've always been under the impression that fully factoring a polynomial meant putting it into the form of a product of first degree and/or constant polynomials. $$(Ax+a)(Bx+b)(Cx+c)...$$ Since the results you've posted contain at least one second degree polynomial (I see an x^2 for example) I'm not sure why it's considered a properly factored output. But perhaps there is a semantic or notational confusion issue.
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revised Factoring polynomials to factors involving complex coefficients
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12
comment Factoring polynomials to factors involving complex coefficients
The specific output I am after is a product of first degree polynomials. For example $x^2+1$ factors into (x-i)(x+i). Another Example: $4x^3-8x^2-x+2$ factors as $(x-2)(2x-1)(2x+1)$
Jul
12
asked Factoring polynomials to factors involving complex coefficients