338 reputation
317
bio website ablona.se
location Stockholm, Sweden
age 53
visits member for 2 years, 1 month
seen 8 hours ago

Managment consultant w a background in Computer Science, rediscovered programming through Mathematica.


Oct
21
reviewed Reviewed Does Mathematica v.8 (or will v.9) run on Windows 8 systems with ARM processors? (like the MS Surface Tablet)
Oct
18
awarded  Custodian
Oct
18
reviewed Reviewed Change variables in differential expressions
Oct
18
comment Change variables in differential expressions
Perhaps you can improve the answer by actually applying the solution to the example in the OP, e.g. n[r](3 r..)?
Oct
18
reviewed Reviewed NDSolve event handler Question
Oct
18
reviewed Reviewed Changing some stuff to Kruskal's Algorithm
Oct
16
reviewed Reviewed Show Legend with 3D ListPlot
Oct
16
reviewed Reviewed 3D Random Walk with Periodic Boundary Conditions
Oct
15
suggested suggested edit on trees tag wiki
Oct
15
accepted Calculate proportion of values for dates
Oct
14
reviewed Reviewed efficient way to count the number of zeros at the (right) end of a very large number
Oct
14
awarded  Nice Question
Oct
14
comment Calculate proportion of values for dates
I am new to MMA, so I have to ask for a pointer to the documentation of first assignment {date, ...} = {1,1..}
Oct
14
awarded  Civic Duty
Oct
14
comment Calculate proportion of values for dates
let us continue this discussion in chat
Oct
14
comment Calculate proportion of values for dates
No, not month, day. Sorry for the confusion.
Oct
14
comment Calculate proportion of values for dates
will try autoLegend. Check the order of "Paris" and "Stockholm" in the AxesLabel part, I think you put in the wrong order.
Oct
14
comment Calculate proportion of values for dates
Split/SplitBy looks promising, didn't know about it.. If I follow your guidance, the solution should be to use Split and Count to get the number of values per date and then use SplitBy and Count to get the number of negative values per date.
Oct
14
comment Calculate proportion of values for dates
Yes, it is a likelyhood function that I am after but for a days (there is about 12000 / 400 = 30 values per days which is ok for me). If I understand your counting to months is done in the {Range[12]... code, will experiment with this. (Stockholm is considered to be in the warm, comfortable, south part of Sweden..)
Oct
14
revised Calculate proportion of values for dates
Clear question