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seen Apr 14 at 21:49

Mar
23
comment Setting parts of a list
+1 as this is the only answer in the spirit of the question (or anyway what I took to be the spirit of the question)
Mar
22
answered How to set the NDSolve method to LSODA
Mar
22
awarded  Outspoken
Mar
20
revised simplifying $\frac{\log x^a}{a} = \log x$
added 4 characters in body
Mar
20
revised simplifying $\frac{\log x^a}{a} = \log x$
added 8 characters in body
Mar
20
comment simplifying $\frac{\log x^a}{a} = \log x$
@Andrzej, why don't you add this to your answer and I'll remove it from mine (to avoid overlap)
Mar
20
revised simplifying $\frac{\log x^a}{a} = \log x$
added 215 characters in body
Mar
20
revised simplifying $\frac{\log x^a}{a} = \log x$
added 194 characters in body
Mar
20
comment simplifying $\frac{\log x^a}{a} = \log x$
this is better posted as a comment, not an answer (as it is not, actually, an answer)
Mar
20
answered simplifying $\frac{\log x^a}{a} = \log x$
Mar
20
comment ordering of functional eigenvalues
But what if they were Sin[x] and Cos[x]? You'd have to use OrderedQ, like Sort does, which would sort them as {Cos[x], Sin[x]}. But then if you define x to be some number, the list will not be ordered for around half the possible values of x.
Mar
20
comment Random data generator
SystemDialogInput["RecordSound"], suggested by @Searke, doesn't seem to work on OS X. If it did I'd have written up some code to play with the least significant bits of the input. These I would a priori expect to be random, but they could well be otherwise due to all sorts of things-so it would have been fun. Alas...
Mar
20
comment Equating matrices (or higher order tensors) element-wise
@Mr.Wizard So do I...
Mar
19
comment Equating matrices (or higher order tensors) element-wise
Yes, I could change 2 to Length@Dimensions[c] to fix that, but there must be a better way
Mar
19
revised Equating matrices (or higher order tensors) element-wise
added 1058 characters in body
Mar
19
comment How to remove repeated permutations?
does my added explanation in the answer help? or the linked question? If not, try asking a more specific question
Mar
19
comment Equating matrices (or higher order tensors) element-wise
Right, I see. He has in mind a symbolic matrix on the left hand side, because this does not work for both numerical (also this is what it seems from his motivation).
Mar
19
comment Equating matrices (or higher order tensors) element-wise
this evaluates A==B, then maps Flatten over the result; is this what you intended? (compare Thread[Flatten /@ (a \[Equal] b)] // Trace to the trace of the code I give in my answer to see what I mean)
Mar
19
answered Equating matrices (or higher order tensors) element-wise
Mar
19
revised How to remove repeated permutations?
added 104 characters in body