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visits member for 2 years, 8 months
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StringTake[ ExampleData[{"Text", "Hamlet"}] <> "@", List /@ {45, 114, 132, 134, 138, 142, 2933, 2939, -1, 2994, 3184, 3189, 3213, 3305, 3364, 3427, 3446, 3473}] // StringJoin


Jul
31
comment In version 10 EvaluationCompletionAction “ShowTiming” no longer gives useful output; any solutions?
I was told weeks ago that this was reported
Jul
30
comment How to generate and label multiple histograms as Query operator(s)?
It used to be documented before the final release. And it will go away, but I am hoping as it goes away, some other function will take its job because I find it pretty useful
Jul
30
comment Automatically lining up two images that have some common elements
Are there other sample pairs of images?
Jul
30
comment Possible bug involving Dataset/Query and RightComposition
It seems like a bug to me. As if only the last ascending operator is applied if the first of the chain is descending. If this is true, you could make any op descending/ascending with something like Select[True &] /* desc1 /*.../* descn /* Function[asc1 /* ... /* ascn@#]
Jul
25
awarded  Enlightened
Jul
25
awarded  Nice Answer
Jul
24
comment Defining a sequence slot programmatically
Where seems to have a definition intended to catch things like Where[{x,y}={2, 3}, f[x,y]] that they added last and is never tried. To fix it, use DownValues[Where] = RotateRight@DownValues@Where
Jul
24
comment Setting and changing MetaInformation for arbitrary objects
@MichaelStern luck. I just felt it was sensible for nested temporal data's to be flattened out, tried it and worked.
Jul
24
comment Possible bug: SparseArray Part assignment loses default value?
@LeonAvery you want a workaround to set the background or to set all the elements to a value?
Jul
24
revised Possible bug: SparseArray Part assignment loses default value?
edited tags
Jul
24
revised Setting and changing MetaInformation for arbitrary objects
added 97 characters in body
Jul
24
answered Setting and changing MetaInformation for arbitrary objects
Jul
24
comment How to generate and label multiple histograms as Query operator(s)?
Perhaps titanic[Composition[Histogram[#, ChartLabels -> Automatic] &, Pivot[#, 2] & ], {"age"}]. (but Pivot is probably going away soon)
Jul
19
comment DeleteDuplicatesBy is not performing as I'd hoped. Am I missing something?
@JacobAkkerboom you are right, that output doesn't make sense to me either
Jul
19
comment DeleteDuplicatesBy is not performing as I'd hoped. Am I missing something?
@JacobAkkerboom I agree. I don't really mind the messages, I take them as bonus warnings. Furthermore, it does work in the sense that it returns what it should (right?. e.g GroupBy[Unevaluated@{Print@"a"; 2 + 2}, Hold, Hold]), even though it leaks. But I hope they started taking the leaks more seriously and not evaluate stuff they don't need to. One sometimes needs to count on "sensible behaviour".
Jul
19
comment DeleteDuplicatesBy is not performing as I'd hoped. Am I missing something?
Nice analysis +1
Jul
19
revised DeleteDuplicatesBy is not performing as I'd hoped. Am I missing something?
added 5 characters in body
Jul
19
comment DeleteDuplicatesBy is not performing as I'd hoped. Am I missing something?
I can't find DeleteDuplicatesBy documentation for anything other than lists and associations
Jul
19
comment Normal // Association // Dataset workaround for some user query operators
A different way to write the same thing could be data[GroupBy[Key["key1"] -> KeyDrop["key1"]], First]
Jul
18
comment Changing mouse appearance at notebook level
@belisarius, put that as an answer, so I can downvote it