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2d
comment Inconsistent Integrate behavior?
My problem is: Following your example: Using a=1 leads to a result which includes the conditional expression. Using a=12 does NOT return the conditional expression, but it should to have a consistent behavior.
Apr
26
comment Inconsistent Integrate behavior?
@Sumit: This makes no sense: I would like to do the integration analytically, thus, why should I use here "12."?
Apr
26
comment Inconsistent Integrate behavior?
shouldn't I get a conditional expr. in the second example?
Apr
26
asked Inconsistent Integrate behavior?
Apr
4
awarded  Notable Question
Oct
27
awarded  Notable Question
Sep
2
awarded  Popular Question
Sep
2
comment import of a opj file (Origin)
unfortunately, even opj2dat failed to convert the file, although it's only a tiny 2D list
Sep
1
asked import of a opj file (Origin)
Aug
24
accepted Table generation with SetDelayed function
Aug
21
asked Table generation with SetDelayed function
Jul
24
awarded  Nice Question
May
16
accepted Applying ReplaceAll to I (imaginary unit)
May
15
comment Applying ReplaceAll to I (imaginary unit)
@SjoerdC.deVries: I understand, thank you for clarifying this to me. It would be nice if this could be stressed in the Documentation.
May
15
revised Applying ReplaceAll to I (imaginary unit)
typo
May
14
comment Applying ReplaceAll to I (imaginary unit)
@SjoerdC.deVries: Did you read the other posts? What is then, in your opinion, the mistake? I mean, it's clear that the behavior is inconsistent. But since I'm not the designer of the called function I have no clue what is going on there.
May
14
revised Applying ReplaceAll to I (imaginary unit)
the behavior of ReplaceAll is inconsistent or at least confusing
May
13
comment Applying ReplaceAll to I (imaginary unit)
Is is difficult to add a reverse procedure?
May
13
comment Applying ReplaceAll to I (imaginary unit)
aah, now I understand, I thought it's necessary to have it in FullForm before replacement, thank you!
May
13
comment Applying ReplaceAll to I (imaginary unit)
Of course, I understand. However, if I precede in my calculation I have a mixture of "normal form" expressions and FullForm and this generates problems when evaluating scalar products like FullForm[{1, 2, 3}].{1, 2, 3}