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Update According to @xzczd in my comment: Simply removing the outermost braces will work, i.e. {0,0},{1,2},{5,3},{6,5}. Original Answer (0,0) (1,2) (5,3) (6,5) worked. To efficiently convert your lists to this form: convertlist[expr_] := StringReplace["(0,0) " <> ToString[expr], {"{{" -> "(", "}}" -> ")", "}, {" -> ") ("}] Comparing ...


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A plot like that in the reference provided in the Question can be obtained as follows. Solve the given equation (with x normalized to a for convenience and without loss of generality): Reduce[x == Exp[1/x]/(5 - 5 Exp[1/x]), x] (* Element[C[1], Integers] && -1 + E^x^(-1) != 0 && -5 + ProductLog[C[1], 5*E^5] != 0 && x == (-5 + ...


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At a crude level, the evaluator that does the TrigExpand can be emulated by a FixedPoint or ReplaceRepeated. If we want to see the steps behind this particular kind of evaluation, it seems possible that a simple substitute for the built-in TrigExpand can be implemented based on FixedPointList instead of FixedPoint, to keep track of the steps. Here is a ...



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