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7

Just tossing a thought out there. Using the following sample data from ListVectorPlot3D, Graphics directives can be applied to VectorStyle to get a shape you desire: vectors = Table[{{x, y, z}, {y, x - x^3, z}}, {x, -1.5, 1.5, 0.2}, {y, -2, 2, 0.2}, {z, -1, 1, 0.1}]; ListVectorPlot3D[vectors, VectorScale -> 0.05, VectorStyle -> ...

2

f = DynamicModule[{col = Black}, DynamicWrapper[Dynamic@Style[#, col], If[CurrentValue["MouseOver"], col = Red; pos = {#2, #3}, col = Black; pos = {}]]] &; With[{d1 = Rest@data}, ListPlot[{{#2, #3}} & @@@ d1, BaseStyle -> {PointSize@.02, 15, Bold}, ...

2

Posting my comments as an answer: Use ScalingFunctions -> "Log". However, as the value of the log-PDF tends to $-\infty$ away from the data, you'll have to set the PlotRange manually to get a reasonable-looking plot. data = RandomVariate[BinormalDistribution[.5], 1000]; SmoothDensityHistogram[data, ScalingFunctions -> "Log", PlotRange -> {-4, ...

1

I guess that the answer is similar to the one given in this answer, which is my case is style1 = {Lighter@Red, Red, Darker@Red} style2 = {Lighter@Blue, Blue, Darker@Blue} data = {{2, 1, 1}, {1, 2, 4}} PieChart[MapThread[Style, {data, {style1, style2}}, 2], ChartLayout -> "Stacked"] Note that I am cheating because I made the data a square matrix to ...

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