# Tag Info

10

Mathematica 10 introduces IntegerName: IntegerName[n] gives a string containing the full English name of the integer n. IntegerName[n,"type"] gives a string of the specified type. Possible types include: "DigitsWords" a combination of three-digit numbers and words "Words" using only words "Approximate" the first few digits ...

9

The following works in both v9 and v10: style = Directive[Thick, Black]; ContourPlot[y - x^2, {x, 0, 1}, {y, 0, 1}, ContourStyle -> Directive[Thick, Black, Opacity[1]], FrameStyle -> style, PlotLegends -> BarLegend[Automatic, Method -> {FrameStyle -> style}]] The idea to use the (undocumented) Method option comes from inspecting the ...

9

Part a response, Because you do not show additional information and do not describe the problem with the code, I show one approach. First we construct some helpers : ClearAll["Global*"] SetDirectory@NotebookDirectory[]; siz1 = 250; siz2 = 500; tex1 = "What a long and interesting and certainly necessary title for \ a panel of functions."; title = ...

9

The reason is that you have empty history because you set $HistoryLength = 0 (as you confirm in the comments). I recommend setting$HistoryLength to be at least 3 in order to get the [Show Full Output] button working in the most practical cases.

8

The following may be useful as starters: WolframAlpha["femme from french to german",{{"Translation:TranslationData", 1}, "ComputableData"}] (* {" Frau | Ehefrau", " Frau"} *)

8

Version 10 introduced some undocumented functionality that makes it easier to explore the style hierarchy. As usual, "undocumented" === "buyer beware". We start by evaluating: StyleManagerOpenStyleManager This does nothing other than trigger the auto-loading of certain symbols. We'll come back to a more interesting use of this symbol later. Now, we ...

8

You can also use MapAt with Invisible or Style[#,White]&: f1 = MatrixForm[MapAt[Invisible, #, Position[#, Except[#2], {2}, Heads->False]]] &; (* or f1 = MatrixForm[MapAt[Style[#,White]&, #, Position[#, Except[#2], {2}, Heads->False]]] &; *) Example: m = RandomInteger[5, {5, 5}]; Row[Prepend[f1[m, #] & /@ {1, 2, 1 | 2}, ...

7

Right, it doesn't work, but you can use this alternative: Grid[{{"The Thick Red Frame"}}, Frame -> True, FrameStyle -> Directive[Red, Thickness@10]]

7

x = E^-n (2 E^-1 + E^2) + E^n (2 E^-2 + E); x /. Times[a_, b_] :> Times[a, ExpToTrig@b] E^n (E + 2 Cosh[2] - 2 Sinh[2]) + E^-n (2 Cosh[1] + Cosh[2] - 2 Sinh[1] + Sinh[2])

7

Because Inactivate acts on Heads of expressions, replaces them with Inactive[h] where h is the Head of the expression and prevents them from evaluating. And in your case the Head of x y is Times: FullForm[x y] Times[x, y] So Inactivate[x y] Gives: Where the Times did not evaluate. Hence, the result you get when you apply TraditionalForm.

7

It sounds like you're merely looking for Row: Cp = 1.5; deltastar = 0.123; Row[{ "The value for ", HoldForm[Subscript[C, p]], " is ", Cp, " and the value for ", HoldForm[Superscript[\[Delta], "*"]], " is ", deltastar, "." }] If this does not work for you please clearly state how it fails so that those issues can be directly addressed.

7

Looks like StringForm can achieve this: Cp = 1.5; deltastar = 0.123; Then: StringForm["The value for 1 is 2 and the value for 3 is 4.", HoldForm @ Subscript[C, p], Cp, HoldForm @ Superscript[\[Delta], "*"], deltastar]

7

The dimming is controlled by the option PrivateCellOptions->{"EvaluationUnmatchedStyle"}. It must be applied at the cell level, but this is easy to do in your example by using CellPrint with the "Print" style to match what Print does. CellPrint@ ExpressionCell[g, "Print", PrivateCellOptions -> {"EvaluationUnmatchedStyle" -> {}}]

7

Add this to your notebook or init file $PrePrint = If[MatrixQ[#], MatrixForm[#], #] &; Then all matrices will automatically display as MatrixForm and If you want to format lists as column vectors also, try$PrePrint = Which[MatrixQ[#], MatrixForm[#], VectorQ[#], ColumnForm[#], True, #] &; Now also

6

x = {3, 1} y = {2, 5} a Defer[x] + b Defer[y] /. First@Solve[a x + b y == {7, 11}, {a, b}] (* x + 2 y *) Note that the output is usable as such: evaluate it and you'll get the combination result. If only integer coefficients are desired, changing the Solve to something like: Solve[a x + b y == {7, 11} && {a, b} \[Element] Integers, {a, b}] ...

6

Here's how to add a permanent menu item and keyboard shortcut for Silvia's solution. (This can be easily adapted to Jens' solution for Mac OS.) 1. Add Package Copy Silvia's first code block that starts with Needs["NETLink"] to a file and save it as UniCodeCopy.m in one of the directories included in $Path. 2. Initialize the Front End Save the ... 6 Will a = -3; Print[Defer[\[FormalA] x + 5 + x^2] /. \[FormalA] -> a] -3 x + 5 + x^2 work for you? 6 Consider this: Inactivate[3*5 - 2 - 3] // FullForm Inactive[Plus][Inactive[Times][3, 5], -2, -3] RunnyKine is correct regarding the cause but he did not really explain the mechanism involved. Formatting rules typically apply to (sub)expressions with certain heads. This has nothing to do with evaluation per se, but rather the patterns in the ... 6 Here is a function that copies a Unicode string to the clipboard using JLink: Needs["JLink"]; InstallJava[]; LoadJavaClass["java.awt.Toolkit", AllowShortContext -> False]; uniclip[s_String] := JavaBlock[ javaawtToolkit`getDefaultToolkit[]@getSystemClipboard[]@setContents[#, #]& @ JavaNew["java.awt.datatransfer.StringSelection", s] ... 6 Something like heldint = HoldForm[Integrate[r^3, {t, 0, 2 Pi}, {r, 0, 2}, {z, r^2, 4}]]; int = ReleaseHold[heldint]; Row[{heldint, " \[LongEqual] ", int, " \[TildeTilde] ", N[int]}] // TraditionalForm 6 TraditionalForm looks nice but it also incurs additional complexity in handling expressions. If you attempt to evaluate a TraditionalForm cell you will be asked if you wish to interpret it as input, and the equivalence is not always complete. Fortunately Mathematica is quite cabable of displaying formatted integrals in StandardForm. If you merely wrap ... 6 You people with your fancy version 10 have it too easy. StringJoin@Reverse@MapIndexed[ToString[#] <> {"", " thousand ", " million ", " billion ", " trillion" }[[First@#2]] &, Reverse@(FromDigits /@ Partition[PadLeft[#, 3 - Mod[#, 3, 1] + # &@Length@#] , 3])] &@ IntegerDigits[123456789] "123 million 456 ... 6 data = Table[(i + j) i (i - j), {i, 1, 2}, {j, 1, 22}]; The first step is to define a function to break up each row in the data into lines not exceeded the specified maximum line length. prep[row_, fieldWidth_, lineLength_] := Module[{items = Floor[lineLength/fieldWidth]}, Partition[row, items, items, 1, {}]] The second step is to do the ... 5 I think I would choose to use MakeBoxes and Defer for this: MakeBoxes[a_^Rational[1, x_], fmt_] := ToBoxes[a^Defer[1/x], fmt] Now: -Sqrt[a - bar] -(a - bar)^(1/2) This also catches cases that use RadicalBox: x^(1/3) // TraditionalForm x1/3 Defer is used to allow the output to be used as input. An alternative is Interpretation but that ... 5 Go To Format > Edit Stylesheet... and add this style to your private stylesheet: Cell[StyleData["Output", "SlideShow"], ShowCellLabel->False] 5 I don't use the command line and haven't tried this but I suspect that SetOptions["stdout", PageWidth -> Infinity] may be what you are after. 5 I post this for illustrative purposes. You can access values. I suggest looking at the properties of your model, e.g. if your model is nlm then nlm["Properties"]. Some data and model: wd = WeatherData["Brisbane", "Temperature", {{2004, 1, 1}, {2013, 12, 31}, "Day"}]; vl = QuantityMagnitude /@ wd["Values"]; bnl = ... 5 EDITED to include Mr.Wizard's replacement for Switch EDITED to cover additional cases Roll your own: quantityWithAppropriatePrefix[quant_Quantity] := Fold[UnitConvert[#1, #2] &, quant, {"Imperial", "SI"}]; quantityWithAppropriatePrefix /@ {Quantity[0.0000011, "Meter"], Quantity[0.0000033, "Feet"]} {Quantity[1.1, "Micrometers"], ... 5 Defer[Quantity][Placeholder["tip"],"Meters"] or HoldForm[Quantity][Placeholder["tip"],"Meters"] The second method requires ReleaseHold to evaluate. 5 I am not familiar with the specific output format you need but I think I can show you how to proceed. dat = Import["ExampleData/caffeine.xyz", {{"VertexTypes", "VertexCoordinates"}}]; dat2 = {#[[1, 1]], #[[All, 2]]} & /@ GatherBy[dat\[Transpose], First]; dat3 = {#, Length@#2, #2} & @@@ dat2; dat3 has this format: dat3 // TableForm$\left( ...

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