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Select the cell containing your output, then choose TraditionaForm from the Convert To submenu of the Cell menu. The cell will then show Update Perhaps this is what you are looking for: (f^(1,0,0))[x, y, z]/(h^(1,0,0))[x, y, z] /. h_[x, y, z] -> h


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If I understand well, what you probably need is first Pane (with its ImageSize option) then Framed. What about this : expr1 = a x^2 + b x + c; expr2 = expr1/d; fixedframe[expr_]:=Framed@Pane[Style[TraditionalForm[expr1], 16], ImageSize -> {200, 50}, Alignment -> Center] then fixedframe[expr1] fixedframe[expr2] The size of the frame ...


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Simple: use Table Sum[i^2, {i, 3}] (* 14 *) Table[i, {i, 3}] (* {1, 4, 9} *) If you want the output to be displayed like a sum, use Row: Row[%, "+"] (* 1 + 4 + 9 *) And when you want to evaluate, simply use Total: Total[%%] (* 14 *) There is another solution (see David's comment): Sum[(HoldForm[#] &)[i^2], {i, 3}] (* 1 + 4 + 9 *) To explain ...


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A look at the FullForm motivates e.g. this: der = Derivative[1, 0, 0][f][x, y, z]/Derivative[1, 0, 0][h][x, y, z]; der /. Derivative[a___][b___][c___] :> Derivative[a][b]



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