New answers tagged machine-precision
2
Ditch the decimal point after the 16 (this makes it a machine precision number):
1/Sqrt[1 - (150^2 10^(-4))/(9 10^16)] - 1
yeilds:
-1 + 200000000/Sqrt[39999999999999999]
7
Calculating eigenvalues involves solving for the roots of the characteristic polynomial, which is of degree equal to the order of the size of the matrix. When you input real numbers, it can search for the roots of the polynomial using numerical techniques. When you input exact integers (or rationals, probably) it tries to find exact answers for the roots of ...
0
Use in the following way also.
SetPrecision[NIntegrate[f[x], {x, 0, 2*Pi}], 15]
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