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As pointed out by MarcoB in the comments, one shouldn't use MatrixForm for calculations (check the question he referred to). As he suggested, this is the real reason Inverse doesn't evaluate. Also, in this case the matrix m is singular. You can easily check that by MatrixRank[m] which yields 2, and also by checking Det[m]==0. How to proceed with m being ...


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I am not sure what the ultimate aim is here. I post this in case it motivates the desired approach. Anything above N=2 is unwieldy: Setup: matg[n_, s_, col_] := Table[Style[Unique[s], col, Bold], {n}] smat[n_, s_, col_] := SparseArray[{i_, j_} :> Style[Unique[s], col, Bold], {n, n}] Example: a = smat[2, "a", Red]; b = List /@ matg[2, "b", ...


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In the second case, the InverseFunction is computed by Solve, similarly to In[1]:= Solve[x == y && -1 <= x <= 1 && Element[y, Reals], x] Out[1]= {{x -> ConditionalExpression[y, -1 < y < 1]}} According to the documentation, Solve gives generic solutions only. Solutions that are valid only when continuous parameters ...



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