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375

I have to confess that I see this as a proper challenge, as I am usually quite creative in finding/combining functions to provide a desired behavior. So I will give it another try. which is generated using box[x_, x1_, x2_, a_, b_] := Tanh[a (x - x1)] + Tanh[-b (x - x2)]; ex[z_, z0_, s_] := Exp[-(z - z0)^2/s] and r[z_, x_] := (*body*).4 (1.0 - .4 ...

198

This might get me suspended from the site butt I cannot resist. The shape you are looking for can probably be approximated (depending how anal you want to be about the outcome) by two assymetric probability distributions. The obvious choices would be a Poasson or a log normal distribution. I will use the latter as it is continuous. Now the bummer is that ...

190

Well, the answer seems to be YES :) Here is my implementation of Minecraft classic game in Mathematica. Let’s start with some screenshots which were taken during the construction of the final scene which will be displayed an the end of this post. Features Blocks are creatable and removable One texture per block Player automatically jumps to the ...

103

Parametric Buttocks Manipulator Manipulate[ ParametricPlot3D[{ (e u^p + (1 + (c - a u) (u - 1)) Cos[t]^2) Sin[t], (e u^p + (1 + (d - b u) (u - 1)) Cos[t]^2) Cos[t], 2 u}, {t, -0.2, Pi + 0.2}, {u, 0, 1.1}, Lighting -> "Neutral", Mesh -> None, PlotStyle -> Directive[Specularity[0], RGBColor[0.92, 0.85, 0.73]], Axes -> False], {{a, ...

78

TL;DR: A package (Mathematica v10) can be found at the very bottom of this post. UPDATES 6: Tiny update: Import can now use the ".bvh" extension to determine the import type. The code that does this is ugly, but I don't see any other way at the moment. out = Import["C:\\Female1_C03_Run.bvh"] 5: Added error checking and registered the package ...

75

Yes we can. The following DashedGraphics3D[ ] function is designed to convert ordinary Graphics3D object to the "line-drawing" style raster image. Clear[DashedGraphics3D] DashedGraphics3D::optx = "Invalid options for Graphics3D are omitted: 1."; Off[OptionValue::nodef]; Options[DashedGraphics3D] = {ViewAngle -> 0.4, ViewPoint ...

66

Here's one way to slice the donut. To draw one half of the sliced donut I'm using a parameterisation of a torus similar to the one on wikipedia, but with v replaced with u + v and v running from 0 to Pi instead of 2 Pi. This means that the cut is actually a double twist loop. pl = ParametricPlot3D[{{Sin[u] (2 + Cos[u + v]), Cos[u] (2 + Cos[u + v]), Sin[u + ...

56

A major point behind the video is that Mobius transformations are simplest when viewed on the sphere. Thus, we'll never actually define a Mobius transformation - we'll do that part on the sphere. Of course, we will need to project back and forth. Here are the stereo graphic projection and it's inverse implemented as compiled functions for speed. This is ...

53

We can do this by building a regular hexagon tile and wrapping it onto a torus: hexTile[n_, m_] := With[{hex = Polygon[Table[{Cos[2 Pi k/6] + #, Sin[2 Pi k/6] + #2}, {k, 6}]] &}, Table[hex[3 i + 3 ((-1)^j + 1)/4, Sqrt[3]/2 j], {i, n}, {j, m}] /. {x_?NumericQ, y_?NumericQ} :> 2 π {x/(3 m), 2 y/(n Sqrt[3])} ] ht = ...

53

Edit: Added the reversal and some refinements ω = 1; posP[t_, φ_] := Sin[ω t + φ] {Cos[φ], Sin[φ]} posL[φ_] := {-#, #} &@{Cos[φ], Sin[φ]} Animate[ Graphics[{PointSize[0.02], Table[{Black, Line[posL[π i]], Hue[i], Point[posP[t, π i]]}, {i, 0, 1, 1/(3π-Abs[9.43-t])}] }, PlotRange -> {{-1.5, 1.5}, {-1.5, 1.5}} ], {t, 0, 6π, 0.2} ]

49

In principle, Non-uniform rational B-splines (NURBS) can be used to represent conic sections. The difficulty is finding the correct set of control points and knot weights. The following function does this. UPDATE (2016-05-22): Added a convenience function to draw a circle or circular arc in 3D specified by three points (see bottom of post) EDIT : Better ...

49

If you want to make several sequences of the Collatz function for turning it into a graph, you probably want to memorize, which parts you already calculated. What we try to do is to create a graph like this (image from xkcd) When we would calculate the whole chain for each number until it (hopefully) reaches the end sequence 8,4,1 we do a lot of work over ...

44

Answer Apparently, the mesh lines generate points which are too close to the triangle vertices, and VRML is not being able to handle them correctly. To prove the theory, try the example without meshes: p = ParametricPlot3D[{(2 + Cos[v]) Sin[u], (2 + Cos[v]) Cos[u], Sin[v]}, {u, 0, 2 Pi}, {v, 0, 2 Pi}, PlotStyle -> Red, Mesh -> None]; ...

44

I'm posting this as a second answer, as it's really a completely different approach. It's also been substantially expanded as of April 25, 2012. While this still doesn't specifically address the question of adding a region, it does plot the countries separately. Of course, each country could be viewed as a region in itself. Our objective is to make a ...

43

First of all let me tell you that you should wait for some great submissions from other members. Maybe @Yu-SungChang will post some FPS game here ;-). I just will give you the prototype I happen to write recently for an unrelated task. I could fly around your example too but it is too slow (and cool ;-) ) - I will demo some more fluid but simple environment. ...

42

Solution 1: Using 3D Texture with Polygons The idea is to use Polygon with 3D texture supported by Texture, but it requires a bit of undocumented hack to make it smooth. The original data set is from Stanford Graphics Group website. The dataset that has been used is CThead, 8-bit tiffs (download). Before proceed, make sure that you have a plenty of memory ...

42

I'd like to expand on Quantum_Oli's answer to give an intuitive explanation for what's happening, because there's a neat geometric interpretation. At one point in the animation it looks like there is a circle of colored dots moving about the center, this is a special case of so called hypocycloids known as Cardano circles. A hypocyloid is a curve generated ...

39

I propose a small modification of the parametrization for the torus that addresses issues with conformality. Try F[t_, u_, r_] := {Cos[t] (r + Cos[u + Sin[u]/r]), Sin[t] (r + Cos[u + Sin[u]/r]), Sin[u + Sin[u]/r]} instead. Next, we wish to choose suitable values for $m, n$ for a given $r$ such that the mapping of the ...

34

Note that ViewPoint is given in specially scaled coordinates which depend on amongst things the size of the bounding box. To get better control over the positioning of the camera you could use ViewVector instead, which is given in terms of the coordinates of the plot. You could for example do something like this: rotateMeHarder1[g_, vertical_, viewpoint0_, ...

34

Yet another method: Let us calculate values of function on appropriate rectangular grids, which we will convert to textures (1 pixel = 1 value). Interpolation between pixels is built-in. f = 2 #1^2 + 2 #2^2 + #3^2 + #1 #2 &; PolyhedronData["Cube"] // N // Normal // toTriangles // texturize[f, 50, Hue, Lighting -> "Neutral", Axes -> True] ...

33

Usage Just use this function with any polyhedron in in form: GraphicsComplex[pts_, Polygon[vertices_, ___]]. When I find time and motivation maybe I will add more DownValues so it can be more general. At the moment you can play with solids given by PolyhedronData[... "Faces"]: polyhedronRandomWalk[ PolyhedronData["DuerersSolid", "Faces"] ] ...

32

If you want to plot a distribution that is three dimensional then first you need to form it! SmoothDensityHistogram plots a smooth kernel histogram of the values $\{x_i,y_i\}$ but as we have three dimensional data here we need the function called SmoothKernelDistribution! data = RandomReal[1, {1000, 3}]; dist = SmoothKernelDistribution[data]; Now you ...

32

Well, an unusual question to answer, what about something like this Plot3D[.7*(1 + Tanh[1 - (2*Y^2 + X^2 + X^4)]) - .3*Exp[-X^2/.0025]* Exp[-(Y - .1)^2/.15] - .2*(Exp[-(X - .7)^2/.02]*Exp[-(Y - .0)^2/.08] + Exp[-(X + .7)^2/.02]*Exp[-(Y - .0)^2/.08]), {X, -1, 1}, {Y, -1, 1}]

31

UPDATE: latest Mathematica 9 functionality This is very easy now with latest Mathematica 9 functionality. Just use Image3D or Raster3D functions: data = Developer`ToPackedArray[With[{step = .03}, ParallelTable[Exp[-(i^2 + j^2 + k^2)^4/.99], {k, -1.2, 1.2, step}, {i, -1.2, 1.2, step}, {j, -1.2, 1.2, step}]]]; Image3D[data, ColorFunction -> #, ...

31

Scientific progress! In v10.3 with all the goodies in AnatomyData we can now use the simple code: Entity["AnatomicalStructure", "Skin"]["Graphics3D"] Zoom in on the appropriate part and you're done. pelvisLoc = AnatomyData[Entity["AnatomicalStructure", "Pelvis"], "RegionBounds"]; Show[ Entity["AnatomicalStructure", "Skin"]["Graphics3D"], ...

30

I sometimes use Pov-Ray to render quantum mechanical wave function data, and I wrote a very basic package that exports simple Mathematica plots and call povray to render the graphics, and then imports it into the notebook. In this way, I can render better looking graphics without leaving Mathematica. Moreover, since the graphics are rendered outside ...

29

Objects obscure their own shadows when viewed from the position of the light source. Consider the following 3D scene: If this scene is illuminated with a light source located at the camera position, the shadow of the cow will land on any part of the walls or floor which is obscured by the cow. Suppose we rasterize this scene with the lighting turned off ...

29

One can also use MeshFunctions: Clear[f]; f = {x, y, z} \[Function] x + Sin[5 z] + y^2; cube = PolyhedronData["Cube", "RegionFunction"]; mesh = 15; RegionPlot3D[cube[x/2, y/2, z/2], {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, MeshFunctions -> {f}, Mesh -> mesh, MeshShading -> ColorData["Rainbow"] /@ Range[0, 1, 1/(mesh + 1)], PlotPoints -> 50, ...

29

Edit I had some time so I've added full surface torus. Old code in edit history. DynamicModule[{x = 2., l = 100., x2 = 2., l2 = 100., grid, fast, slow}, Grid[{{ Graphics3D[{ Dynamic[Map[{Blue, Polygon[#[[{1, 2, 4, 3}]]]} &, Join @@@ (Join @@ Partition[#, {2, 2}, 1]) ]&[ ...

29

This is the Collatz function I know: Collatz[1] := {1} Collatz[n_Integer] := Prepend[Collatz[3 n + 1], n] /; OddQ[n] && n > 0 Collatz[n_Integer] := Prepend[Collatz[n/2], n] /; EvenQ[n] && n > 0 Generating a graph from this is easy: Graph[(DirectedEdge @@@ Partition[Collatz[#], 2, 1]) & /@ Range[500] // Flatten // Union, ...

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