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As far as I know, there is no easy, general way to handle this kind of algebra with Sum expressions. What follows is an attempt to use replacement rules to handle a wider range of cases than chris's example. I don't consider it to be the canonical answer that is required, but perhaps someone might be able to use it as a starting point. I use Inactive on ...


1

I usually use Simplify with assumptions: Simplify[ Reduce[1/(E^0)^x + 1/(E^1)^x + 1/(E^3)^x == 0, x], C[1] ∈ Integers] (* x == I π (1 + 2 C[1]) + Log[-Root[1 + #1^2 + #1^3 &, 1]] || x == 2 I π C[1] + Log[Root[1 + #1^2 + #1^3 &, 2]] || x == 2 I π C[1] + Log[Root[1 + #1^2 + #1^3 &, 3]] *) That way I'm fairly confident the ...



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