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First we can see that ${\frac{(6k+1)^{k}}{(2k+5)^{k}}}$ behaves asymptotically as $3^k$, while $(z-2i)^k$ is divergent if $\|z-2i\|>1 $, however when $\|z-2i\|<1 $ it is convergent. For $\|z-2i\|=1$ this criterion is not conclusive. On the other hand we can carefully extend this argument to the full sequence, so we need only $\|z-2i\| < ...


3

k[] is function defined by you and tri is making UndirectedEdge-s k[j_List] := Block[{t = j[[1]], r = j[[2]], i = j[[3]]},(2 t - 1) 2^(-i + r) 3^(-1 + i)] tri[{t_, r_, i_}] := {{t, r, i} <-> {t, r + 1, i}, {t, r + 1, i} <-> {t, r + 1, i + 1},{t, r + 1, i + 1} <-> {t, r, i}} I remaked your code like this for making Graph. d = 4; data ...



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