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You can write a function that processes the boxforms produced by TraditionalForm to replace the parentheses by square brackets: tF=RawBoxes[ToBoxes[TraditionalForm[#]]/.{"("->"[",")"->"]"}]&; TraditionalForm/@{C[x,y], Sin[x], f[x,y], H[x], h[x,y,z], H[x,y], h[{x,y}]} (* {C[x,y], sin(x), f(x,y), H(x), h(x,y,z), H(x,y), h({x,y})} *) tF/@{C[x,y], ...


0

I believe it is because some upper-case letters are interpreted as functions K[x,y] //TraditionalForm (* $K[x,y]$ *) Note that K is a system name ?? K (* $K$ is a default generic name for a summation index in a symbolic sum. *) However, letters that are not functions are not: B[x,y] //TraditionalForm (* $B(x,y)$ *) All lower-case functions are ...


8

ReplaceAll ReplaceAll does not behave as a Listable head. If it did it would be broken. Consider: SetAttributes[brokenReplaceAll, Listable] brokenReplaceAll[{1, 2, 3}, {{2 -> "b"}, {2 -> "X"}}] Thread::tdlen: Objects of unequal length in brokenReplaceAll[{1,2,3},{{2->b},{2->X}}] cannot be combined. >> If it were Listable then arbitrarily ...


10

Yes, they are considered pseudo-listable. Often they are implemented with something similar to f[x_, a_List] := f[x, #]& /@ a


1

You can't do this. If correct behaviour is f[{{1,2},{3,4}}] -> {f[{1,2}],f[{3,4}]} then what is correct behaviour for f[{1,2}] ??? Clearly the second expression has no idea that it came from a previous application of f unless you find some way to tell it. Map is the simple and correct way of achieving what you want; I don't believe that it is ...



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