Tag Info

New answers tagged


The following approach transforms ans1 to ans2 and points the way to more general approaches. As noted in the Question, Simplify returns ans1 unchanged. Introducing a ComplexityFunction that defines fewer symbols as less complex helps some. cf[e_] := LeafCount[e] + 100 Count[e, _Symbol, Infinity] Simplify[ans1, ComplexityFunction -> cf] (* ...

Top 50 recent answers are included