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How can I factor my trigonometric equation?
The equation $$3\sin^2 x - 3\cos x -6\sin x + 2\sin 2x + 3=0$$ has a solution $x = 0$. That means it has a factor of $\cos x - 1$. I tried to write the given equation has the form $$(\cos x - ...
Mar 31 '13 at 2:08
newest factorization trigonometry questions feed
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