Tagged Questions
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votes
0answers
78 views
Solve equations real and imaginary part separately
For my system of equations, the procedure described in Solving complex equations of using Reduce works no more. How can I separate the real and imaginary part of ...
1
vote
1answer
131 views
Stop Mathematica from giving imaginary solutions
I have the following equation:
$$D=\frac{1}{64} \pi A ^3 B \sin \left(C\right)-\frac{1}{2} \pi A B \sin \left(C\right)$$
which I want to solve for $A$. The equation is cubic in $A$ so this should ...
1
vote
1answer
125 views
How can I get the solution of complicated implicit function?
The question is what is the method to solve the implicit function has real and imaginary number.
For example, The function is F(x,y)=(-I*x + 2*y^2)^2 + x^2 - 4*y^4*Sqrt[1 - I*x/(y^2)].
Although I ...
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votes
3answers
442 views
Solving cubic equation for real roots
I'm looking to solve the following cubic equation for x:
$\beta\, x^3 - \gamma \,x = c$. I have plugged in some sample values ($\beta = 2$, $\gamma = 5$ and $c = 2$). When I try to solve this ...
1
vote
1answer
345 views
Forcing FindRoot to return only real solutions
FindRoot documentation reports that if the Equation and the initial point are reals, the solutions are searched in the real domain.
However, in the following case I ...
0
votes
1answer
101 views
Manipulate[]'ing complex roots of an equation using a 2D slider [closed]
I want to make a demonstration of how the complex roots of a polynomial change when I alter the coefficients. Here is my attempt:
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3
votes
2answers
308 views
Is there a way to solve the Apollonius Circle problem in Mathematica?
Assuming x, a, and b are complex numbers, is there a way to reduce the equation Abs[x - a] == k Abs[x - b] to something like ...
3
votes
4answers
876 views
Solving complex equations
I feel like I am missing a basic, but key point when using Mathematica's Solve or Reduce.
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8
votes
2answers
519 views
RootSearch for complex or multiple equations
First the background. I'm trying to solve for the roots of a rather messy complex equation. This is not the exact equation, but it's a decent (simpler) stand in:
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