Tagged Questions
4
votes
1answer
119 views
Combinations which do not have elements in common
I can choose 2 letters from the four letters $\{A,B,C,D\}$ in 6 combinations using the combination formula
$$\frac{n!}{ r! (n-r)!}$$
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7
votes
3answers
461 views
Probability problem — Rube Goldberg solution?
A user posted this question on StackOverflow which was closed as off topic:
3 people are playing a game with a standard 52 card deck. Each player is given 2 cards each, possible cards and their ...
