# How to order a polynomial in descending powers of x? [duplicate]

This should be very simple, even silly If I ask this mathematica

 Expand [(x + 1) (x + 2) (x + 3)]


Mathematica delivers me well

 6 + 11 x + 6 x ^ 2 + x ^ 3


as achieving this result

x ^ 3 + 6 x 2 + 11 x +6

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## marked as duplicate by MarcoB, Dr. belisarius, ciao, Bob Hanlon, Mr.Wizard♦Jun 13 '15 at 2:33

This question was marked as an exact duplicate of an existing question.

Plus[ ] is Orderless ... – Dr. belisarius Jun 12 '15 at 22:16
expr = (x + 1) (x + 2) (x + 3); expr // Expand // TraditionalForm – Bob Hanlon Jun 12 '15 at 23:39
thanks,ok , puff very easy :( – Fernando Silva Jun 13 '15 at 1:48
Related: (6358), (9483), (9570), (15744), (20714), (30216) – Mr.Wizard Jun 13 '15 at 2:30

PolynomialForm[(x + 1) (x + 2) (x + 3) // Expand, TraditionalOrder -> True]

The problem with PolynomialForm[] is that it is merely a wrapper, like MatrixForm[] for matrices. So, this makes things display pretty, but it should not be given as input for further calculations. You can copy the output, however.