Mathematica Stack Exchange is a question and answer site for users of Mathematica. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Background: consider the following code-snippet.

    Table[Setter[Dynamic[idx, (idx = #1) &],
      i*6 + j, 
    Graphics[{Blue, Disk[]}, ImageSize -> 20]], 
    {i, 0, 1}, {j, 6}]]

This code creates two rows of clickable disk images. So if idx=10 is run, the 10th disk looks pressed. I want to make this control multi-selectable. So if idx={1,12} run, the first and last disks look pressed. ( In my application the disks may have different colors, edge properties and opacity. ) - See also: What is an efficient way of selecting multiple colors via Manipulate?

Question: How to create "a multi-selectable setterbar with colored buttons" ? ( preferably based on the snippet above, but not necessarily ).

share|improve this question
up vote 5 down vote accepted

Does this provide the functionality you are looking for? Note that a multi-selectable SetterBar is a TogglerBar. The only problem with the latter is that it cannot be partitioned into a multi-row grid. For your particular problem, I would rather use Button instead of Setter:

list = {};

   DynamicModule[{pressed = False}, With[{idx = i*6 + j},
     Button[Graphics[{Blue, Disk[]}, ImageSize -> 20], 
      pressed = ! pressed; 
      list = If[pressed, Append[list, idx], DeleteCases[list, idx]], 
      Appearance -> Dynamic@If[pressed, "Pressed", Automatic]]]],
   {i, 0, 1}, {j, 6}]]

Mathematica graphics

A somewhat different approach is to concatenate multiple TogglerBars: this has some drawbacks, as the output is always sorted (if not then output order depends on the order of clicks and the order of TogglerBar rows).

TogglerGrid::usage = 
  "TogglerGrid[x, {val.1, val.2, ...}, n] represents a \
TogglerBar-like control (with setting x and with toggler buttons for \
values val.i to include in the list x), but with togglers arranged in \
a grid, with a maximal n elements per row.";

TogglerGrid[var_, ref_] := TogglerGrid[var, ref, Length@ref];
TogglerGrid[Dynamic[var_], list_List, n_] := Module[
   {set, ref = Evaluate@list, temp},
   temp = {} & /@ ref;
   set = TogglerBar[
        Function[{$x}, temp[[#]] = $x; 
         var = Sort@(Join @@ temp)]], {ref[[#]]}] & /@ 
    Partition[set, n, n, {1, 1}, {}],
    Alignment -> {Center, Center},
    Spacings -> {0, 0}]
TogglerGrid[var_, arg___] := 
  Module[{dummy = var}, TogglerGrid[Dynamic@dummy, arg]];

Test the function:

x = {};
 Table[Graphics[{Hue@RandomReal[], Disk[]}, ImageSize -> 20], {10}],

Mathematica graphics

share|improve this answer
I think so, will try it now. – nilo de roock Jun 28 '12 at 10:02
In your example I would like to have {5,7,9} as a result. – nilo de roock Jun 28 '12 at 10:06
@ndroock1: Please see edit. It is more along the lines of your posted code. – István Zachar Jun 28 '12 at 10:10
That does it, although your previous answer had some nice features regarding building the grid. – nilo de roock Jun 28 '12 at 10:19
@ndroock1: I re-added TogglerGrid. I only removed it previously because I realized it is not exactly an answer to your question. Hope it can be of any use. – István Zachar Jun 28 '12 at 12:00

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.